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Allisa [31]
3 years ago
7

Which figure represents the final image after composition ry-axis ◦ T3, –1 is applied to rectangle LMNP? How is it figure 4?

Mathematics
2 answers:
ki77a [65]3 years ago
7 0
The answer is D. Hope this helps
Crank3 years ago
4 0
The answer you seek is D. 4
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Solve the following equation for B be sure to take into account whether a letter is capitalized or not.
const2013 [10]

Answer:

B = <u>d - 3f²</u>

         5M

Step-by-step explanation:

d -3f² = 5 B B

5 BM = d - 3f²

B = <u>d - 3f²</u>

         5M

6 0
3 years ago
Read 2 more answers
Help me with these 3 plzz!!! plzzzzz
Harrizon [31]
I tried my best with 1, 2, and 3

6 0
2 years ago
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A test is used to assess readiness for college. In a recent​ year, the mean test score was 20.3 and the standard deviation was 4
Vlada [557]

Answer:

\mu = 20.3

\sigma = 4.9

And we can find the limits in order to consider values as significantly low and high like this:

Low\leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5

High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

For this case we can consider a value to be significantly low if we have that the z  score is lower or equal to - 2 and we can consider a value to be significantly high if its z score is  higher tor equal to 2.

For this case we have the mean and the deviation given:

\mu = 20.3

\sigma = 4.9

And we can find the limits in order to consider values as significantly low and high like this:

Low \leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5

High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1

6 0
3 years ago
Given that vector p=i+2j-2k and q=2i-j+2k, find two vectors m and m satisfying the condition;
Stels [109]

9514 1404 393

Answer:

  • m = j +k
  • n = 2i +k

Step-by-step explanation:

There are <em>an infinite number of possibilities</em>. Any vector whose dot-product with p is zero will be perpendicular to p.

Let m = 0i +1j +ak. Then we require ...

  m·p = 0 = 0×1 +1×2 +a(-2)   ⇒   0 = 2 -2a   ⇒   a = 1

m = 0i +1j +1k

__

Let n = 2i +0j +bk

  n·p = 0 = 2×1 +0×2 +b(-2)   ⇒   2 -2b = 0   ⇒   b = 1

n = 2i +0j +1k

6 0
2 years ago
12<br> The value of x must be greater than<br><br> a .0<br> B.1<br> C.3<br> D.7
Likurg_2 [28]

Answer:

must be greater than 7

Step-by-step explanation:

using pythagoras theorem

a^2=b^2-c^2

x^2=15^2-12^2

x^2=225-144

x^2=81

take square root both sides

√x^2=√81

x=9

and 9 is greater than 7

7 0
3 years ago
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