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Alexxandr [17]
3 years ago
7

PLEASE HELP ME :) !!!!!!

Mathematics
1 answer:
balandron [24]3 years ago
6 0
The correct answet is 15a
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Determine the greatest common factor for the pair of numbers.
Mnenie [13.5K]

Answer: C

<u>Step-by-step explanation:</u>

     28                 40

      ∧                   ∧

     4 7               4 10

     ∧                 ∧   ∧

    2 2              2 2 2 5

28: <u>2 * 2</u> * 7

40: <u>2 * 2</u> * 2 * 5

What do they have in common?  two 2s

GCF: 2 * 2 = 4


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3 years ago
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Boarding Kennel Problem In a boarding kennel, dogs number 12 more than 2 times the number of cats. If there are 75 animals, how
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What is the value of m<br> What is the value of n
NeTakaya

Answer:

Step-by-step explanation:

M is 90 degrees anytime you see that square it equals 90 and any time you see that half circle that is obtuse so more than 90 degrees and doing the math the answer to n would be around 127

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3 years ago
Jada wrote 10 000 000 using scientific notation as<br> 10 - 106<br> Is Jada correct?
babymother [125]
I don’t understand it
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3 years ago
) Determine the probability that a bit string of length 10 contains exactly 4 or 5 ones.
yanalaym [24]

Answer: 0.4512

Step-by-step explanation:

A bit string is sequence of bits (it only contains 0 and 1).

We assume that the  0 and 1 area equally likely to any place.

i.e. P(0)= P(1)= \dfrac{1}{2}

The length of bits : n = 10

Let X = Number of getting ones.

Then , X \sim Bin(n=10,\ p=\dfrac{1}{2})

Binomial distribution formula : P(X=x)=^nC_x p^x q^{n-x} , where p= probability of getting success in each event and q= probability of getting failure in each event.

Here , p=q=\dfrac{1}{2}

Then ,The probability that a bit string of length 10 contains exactly 4 or 5 ones.

P(X= 4\ or\ 5)=P(x=4)+P(x=5)\\\\=^{10}C_4(\dfrac{1}{2})^{10}+^{10}C_4(\dfrac{1}{2})^{10}

=\dfrac{10!}{4!6!}(\dfrac{1}{2})^{10}+\dfrac{10!}{5!5!}(\dfrac{1}{2})^{10}

=(\dfrac{1}{2})^{10}(\dfrac{10!}{4!6!}+\dfrac{10!}{5!5!})

=(\dfrac{1}{2})^{10}(210+252)

=(0.0009765625)(462)

=0.451171875\approx0.4512

Hence, the  probability that a bit string of length 10 contains exactly 4 or 5 ones is 0.4512.

3 0
4 years ago
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