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VLD [36.1K]
3 years ago
12

Please help me it’s due today and idk math .

Mathematics
2 answers:
Ulleksa [173]3 years ago
8 0

Answer:

you need to ask one bye one. easyer for us

Fofino [41]3 years ago
4 0
1: C

2:A

3:cant see choices answer is n>5

4:D

5: A

6:can’t see choices answer is x>-6
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An economist uses the price of a gallon of milk as a measure of inflation. She finds that the average price is $3.82 per gallon
salantis [7]

Answer:

(a) The standard error of the mean in this experiment is $0.052.

(b) The probability that the sample mean is between $3.78 and $3.86 is 0.5587.

(c) The probability that the difference between the sample mean and the population mean is less than $0.01 is 0.5754.

(d) The likelihood that the sample mean is greater than $3.92 is 0.9726.

Step-by-step explanation:

According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

n=40\\\mu=\$3.82\\\sigma=\$0.33

As <em>n</em> = 40 > 30, the distribution of sample mean is \bar X\sim N(3.82,\ 0.052^{2}).

(a)

The standard error is the standard deviation of the sampling distribution of sample mean.

Compute the standard deviation of the sampling distribution of sample mean as follows:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

    =\frac{0.33}{\sqrt{40}}\\\\=0.052178\\\\\approx 0.052

Thus, the standard error of the mean in this experiment is $0.052.

(b)

Compute the probability that the sample mean is between $3.78 and $3.86 as follows:

P(3.78

                               =P(-0.77

Thus, the probability that the sample mean is between $3.78 and $3.86 is 0.5587.

(c)

If the difference between the sample mean and the population mean is less than $0.01 then:

\bar X-\mu_{\bar x}

Compute the value of P(\bar X as follows:

P(\bar X

                    =P(Z

Thus, the probability that the difference between the sample mean and the population mean is less than $0.01 is 0.5754.

(d)

Compute the probability that the sample mean is greater than $3.92 as follows:

P(\bar X>3.92)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{3.92-3.82}{0.052})

                    =P(Z

Thus, the likelihood that the sample mean is greater than $3.92 is 0.9726.

3 0
3 years ago
Help me plz now plz help me asap​
loris [4]

\\ \sf\longmapsto 0.49=\dfrac{49}{100}

\\ \sf\longmapsto 0.093=\dfrac{93}{1000}

\\ \sf\longmapsto 0.021=\dfrac{21}{1000}

\\ \sf\longmapsto 0.103=\dfrac{103}{1000}

6 0
3 years ago
I need help on this one question. Please help me. Find the area of the shaded region. It says round to the nearest tenth if nece
schepotkina [342]
30.44 but it depends how you do the problem
5 0
3 years ago
What is a number between 7.833 and 7.834
dalvyx [7]

7.8335 is a number between 7.833 and 8.834

3 0
3 years ago
Read 2 more answers
0.4(2x-9)-0.6(4x+5)=
masha68 [24]

Answer:

From what I can comprehend I believe the answer is <em>3.2x + -4</em>

Step-by-step explanation:

0.4(2x-9) = 0.8x - 9

0.8x - 9 - 0.6(4x+5)=

0.8x - 9 + 2.4x+5

0.8+2.4 = 3.2x

-9 + 5 = -4

3.2x + -4

5 0
3 years ago
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