Answer:
Step-by-step explanation:
3x-5(-4)=23 (1,-4)
3x+20=23
-20
3x=3/3
x=1
Answer:
137 races
Step-by-step explanation:
822/6=137
so if there was 822 people and the limit for the races were 6 people, there would have to be 137 races for all the people.
Answer: (5,8)
Step-by-step explanation:
So this is a matter of using a system of linear equations
To start if a total of 13 people got a ticket then we know that
x+y=13
x and y being explained in the problem
then if adult tickets are $40 and children tickets are $20 and the total cost is 360 we can set up the next equation
40x+20y=360
<em>If you were to plug in 1 lets say into x that means that 1 person bought a ticket for $40 this shown by 40 (1) this is the same premise for the childrens tickets.</em>
now we have
x+y=13
40x+20y=360
now we can solve by eliminating one of the variables this is done by either getting rid of the x or y and solving for the other. I solved for the y value first this looks like
-40(x+y=13)
40x+20y=360
Distribute the -40 to each value
giving you
-40x-40y=-520
40x+20y=360
add these together from the top down
the x's cancel leaving
-20y=-160
then isolate the y value by dividing both sides by -20
-20y/-20=-160/-20
leaving you with your y point
y=8
This is how many childrens rickets were sold now we can plug into the first linear equation
x+8=13
now easy subtration to isolate the x point
x+8-8=13-8
x=5
Finally leaving you with point (5,8)
<span>The largest possible digit sum = 9 + 9 = 18, so no remainder can be > 17.
</span><span>Working down from the top:
99/18 → remainder 9
98/17 → remainder 13
89/17 → remainder 4
97/16 → remainder 1
88/16 → remainder 8
79/16 → remainder 15
After that the divisor is 15 or less,
so the remainder is 14 or less,
and so the largest remainder is 15,
from 79 = 4 * 16 + 15.</span>
