solution:
3x-2y=1 , -9x-6y=-3.
solution system can be represent in (13,0) ( 1 3 , 0 ).
Answer:
Jenna had 25 quarters and 15 dimes.
Step-by-step explanation:
Let Q = the number of quarters and D = the number of dimes.
Then:
1) Q+D = 40 "One week she had 40 coins, all of them dimes and quarters...."
2) 0.25Q+0.1D = $7.75 "...she had a total of $7.75."
Rewrite equation 1) as: D = 40-Q and substitute into equation 2).
2a) 0.25Q+0.1(40-Q) = 7.75 Simplify the left side.
2b) 0.25Q+4-0.1Q = $7.75 Subtract 4 from both sides.
2c) 0.25Q-0.1Q = 3.75 Combine the like-terms on the left side.
2d) 0.15Q = 7.75 Divide both sides by 0.15
2e) Q = 25 and:
D = 40-Q
D = 40-25
D = 15
Jenna had 25 quarters and 15 dimes.
Hi there!
The constant term would be 15.
A constant term is a term that does not or can not be changed.
Hope this helps !
A =7
7^2*3.14*7 sorry I did the equation wrong at first
Answer:
The probability is 
Step-by-step explanation:
From the question we are told that
The capacity of an Airliner is k = 300 passengers
The sample size n = 320 passengers
The probability the a randomly selected passenger shows up on to the airport

Generally the mean is mathematically represented as
=>
=>
Generally the standard deviation is

=> 
=> 
Applying Normal approximation of binomial distribution
Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as

Here 
=>
Now applying continuity correction we have
=> ![P(X >300 ) = P(Z > \frac{[300.5] - 307.2}{3.50} )](https://tex.z-dn.net/?f=P%28X%20%20%3E300%20%29%20%3D%20%20P%28Z%20%3E%20%20%5Cfrac%7B%5B300.5%5D%20-%20307.2%7D%7B3.50%7D%20%29)
=> 
From the z-table

So
