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ahrayia [7]
3 years ago
7

Ramon's hockey camp was four and a half hours long. If the camp ended at 11:45 a.m., what time did it start?

Mathematics
2 answers:
4vir4ik [10]3 years ago
8 0

Answer:

the training started at 7:15 a.m

madam [21]3 years ago
6 0

Answer:

7:15 am.

Step-by-step explanation:

Subtracting  4 hours from  11 :45 am we get 7:45 am.

Subtracting  a further  half an hour gives  7:15 am.

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Answer:

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DanielleElmas [232]

Answer:

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Sequence,S: 8,14,22,32 ,44, 58, 74...

First differences of S: 6,8,10,12,14,16,...

Second differences of S: 2,2,2,2,2,2,....

It is indeed a quadratic since the 1st differences that are the same are the second differences.

So the 1st term is 8. If the 0th term was listes it would be 4 since 8-4=4 and 6-4=2.

This means our quadratic it is in the form

y=an^2+bn+c where c=4.

So we have y=an^2+bn+4.

Now we can find a and b using two points from our sequence to form a system of equations to solve.

(1,8) gives us 8=a(1)^2+b(1)+4

Simplifying gives 8=a+b+4

Subtracting 4 on both sides gives: 4=a+b

(2,14) gives us 14=a(2)^2+b(2)+4

Simplifying gives 14=4a+2b+4

Subtracting 4 on both sides gives 10=4a+2b

So we have the following system to solve:

4=a+b

10=4a+2b

I'm going to solve using elimination/linear combination style.

Dividing second equation by 2 gives the system as:

4=a+b

5=2a+b

Subtract the 2nd equation from the first gives:

-1=-1a

This implies a=1 since -1=-1(1) is true.

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8 0
2 years ago
Anyone know the answer
Arlecino [84]

Answer: A: 2


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3 0
2 years ago
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Mila [183]

Answer:

<u>$4</u> is spent on a big pail and <u>$2</u> is spent on a small pail.

Step-by-step explanation:

Given:

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A small pail cost half as much as each big one.

Now, to find the amount spent on a big pail and on a small pail.

Let the cost of a big pail be x.

And the cost of small pail be \frac{x}{2} .

As given, there are 2 big pails.

And the total money spent = $10.

According to question:

(x+x)+\frac{x}{2}=10

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<em>Multiplying both sides by 2 we get:</em>

5x=20

<em>Dividing both sides by 5 we get:</em>

x=4.

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<em>So, the cost of a small pail</em> = \frac{x}{2} =\frac{4}{2}=\$2.

Therefore, $4 is spent on a big pail and $2 is spent on a small pail.

6 0
3 years ago
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Semenov [28]
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63=4w
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l=2w-3
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This answer doesn't add up so if you meant the COMBINED width then:

P=w+(2w-3)
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63=3w
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l=2(21)-3
l=42-3
l=39

(This answer checks out so this is probably what you meant hope I helped)
7 0
3 years ago
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