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IceJOKER [234]
3 years ago
11

Please help I am so lost; help is much appreciated

Mathematics
1 answer:
netineya [11]3 years ago
6 0
\bf \cfrac{x^3+5x^2+3x-10}{x+4}\impliedby x+4=0\implies x=\stackrel{our~divisor}{-4}\\\\
-------------------------------\\\\
\begin{array}{r|rrrrrrr}
-4&&1&5&3&-10\\
&&&-4&-4&4\\
--&&--&--&--&--\\
&&1&1&-1&\boxed{-6}&\leftarrow remainder
\end{array}
\\\\\\
1x^2+1x^1-1+\frac{-6}{x+4}\implies x^2+x-1+\frac{-6}{x+4}
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LuckyWell [14K]

Answer:

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Step-by-step explanation:

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\bar X_1 = 1085 sample mean for group 1

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s_2 = 61 sample deviation for group 2

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Alternative hypothesis: \mu_1 \neq \mu_2

And the statistic is given by:

t = \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}}

And replacing we got:

t = \frac{1085-1034}{\sqrt{\frac{52^2}{10} +\frac{61^2}{15}}} = 2.240

The degrees of freedom are given by:

df = n_1 +n_2 -2 = 10+15-2= 23

And the p value would be:

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Since the p value is lower than the significance level we have enough evidence to conclude that the true means are different at 5% of significance

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