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kap26 [50]
3 years ago
10

Find the equation (in terms of x) of the line through the points (-3,1) and (5,3)

Mathematics
1 answer:
maxonik [38]3 years ago
4 0

Answer:

(y-3)=(1/4)(x-5) or (y-1)=(1/4)(x+3)

Step-by-step explanation:

point slope formula: (y-y1)=m(x-x1)

slope formula: (y2-y1)/(x2-x1)

slope = m

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2 years ago
Let line $l_1$ be the graph of $5x + 8y = -9$. Line $l_2$ is perpendicular to line $l_1$ and passes through the point $(10,10)$.
SashulF [63]

Answer:

m + c = - 4.4

Step-by-step explanation:

Line 1 is given by the equation 5x + 8y = -9, ⇒ y = - \frac{5}{8} x - \frac{9}{5} ........(1) {In slope-intercept form}

If line 2 is perpendicular to the line 1 then the equation of line 2 will be  

y = \frac{8}{5} x + c  ........ (2), where c is a constant. {Since the product of the slopes of two perpendicular straight line is -1}

Now, the line 2 passes through the point (10,10).

So, from equation (2), we get,

c = y - \frac{8}{5} x = 10- \frac{8 \times 10}{5} = - 6

Therefore, the equation of line 2 will be y = \frac{8}{5} x - 6

This equation is in y = mx + c form where m = \frac{8}{5} = 1.6 and c = - 6

Hence, m + c = 1.6 - 6 = - 4.4 (Answer)

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Step-by-step explanation:

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