Find the equation (in terms of x) of the line through the points (-3,1) and (5,3)

Mathematics

1 answer:

maxonik [38]3 years ago

4 0

Answer:

(y-3)=(1/4)(x-5) or (y-1)=(1/4)(x+3)

Step-by-step explanation:

point slope formula: (y-y1)=m(x-x1)

slope formula: (y2-y1)/(x2-x1)

slope = m

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Find the solutions of the quadratic equation -9c² +2 +3 = 0.

Tresset [83]

Given that,

An equation : -9c² +2c +3 = 0

To find,

Find the value of x.

Solution,

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We can solve it using the formula as follows :

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Here, a = -9, b = 2 and c =3

Put the values,

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Read 2 more answers

Which is the value of this expression when a=5 and k=-2

Zinaida [17]

Answer:

Option C is correct.

Step-by-step explanation:

We are given the expression:

$(\frac{3^2a^{-2}}{3a^{-1}})^k$

The value of a =5 and k = -2

Putting the values and solving

$=(\frac{3^2*5^{-2}}{3*5^{-1}})^-2\\=(\frac{3^{2-1}}{5^{-1+2}})^-2\\=(\frac{3^{1}}{5^{1}})^-2\\\\=(\frac{3}{5})^-2\\if \,\,a^{-1} \,\,then\,\, 1/a\\=\frac{(3)^{-2}}{(5)^{-2}}\\ Can\,\,be\,\,written\,\,as\\\\=\frac{(5)^{2}}{(3)^{2}} \\=\frac{25}{9}$