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3 years ago

What value of x will satisfy the equation 0.2(x −2,700) = x?

1 answer:

4 0

X = -675
I hope this helps! :)
Solve for x, distibutive 0.2:0.2x - 540
Subtract 0.2x to each side: -540 = x - 0.2x
Combine x: -540 = 0.8x
Divide 0.8 to each side: x = -540/0.8 = -675

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The circumference of a circle is approximately 131.88 centimeters What is the area of the shaded region (6/10 of a circle)

scZoUnD [109]

Answer:

82.97cm^2

Step-by-step explanation:

Given data

Circumference= 131.88 centimeters

We want to find the area of 6/10 part of a circle

Firstly, let us find the area of the circle

We need to get the radius

C= 2πr

131.88= 2*3.142*r

131.88=6.284r

r= 131.88/6.284

r=20.98 cm

Area= πr^2

Area= 3.142*20.98^2

Area= 3.142*440.16

Area= 1382.98cm^2

Hence 6/10 of a 1382.98

=0.06*1382.98

=82.97cm^2

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3 years ago

Given the following exponential function, identify whether the change represents growth or decay, and determine the percentage r

BARSIC [14]

Answer:

Dada la siguiente función exponencial, identifique si el cambio representa crecimiento o disminución, y determine la tasa porcentual de aumento o ...

Step-by-step explanation:

3 0

2 years ago

Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 47.3 m

Marta_Voda [28]

Answer:

$\bar X = \frac{2276}{48}=47.417$

If we compare this value with the 47.3 proposed we have the following error

$Error = \frac{|Actual-real|}{real}*100 = \frac{|47.417-47.3|}{47.3}*100 =0.247\%$

The computed mean is close to the actual mean because the difference between the means is less than 5%.

Step-by-step explanation:

Assuming the following dataset:

Speed 42-45 46-49 50-53 54-57 58-61

Freq. 21 15 6 4 2

And we are interested in find the mean, since we have grouped data the formula for the mean is given by:

$\bar X = \frac{\sum_{i=1}^n x_i f_i}{\sum_{i=1}^n f_i}$

And is useful construct a table like this one:

Speed Freq Midpoint Freq*Midpoint

42-45 21 43.5 913.5

46-49 15 47.5 712.5

50-53 6 51.5 309

54-57 4 55.5 222

58-61 2 59.5 119

Total 48 2276

And the mean is given by:

$\bar X = \frac{2276}{48}=47.417$

If we compare this value with the 47.3 proposed we have the following error

$Error = \frac{|Actual-real|}{real}*100 = \frac{|47.417-47.3|}{47.3}*100 =0.247\%$

The computed mean is close to the actual mean because the difference between the means is less than 5%.

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3 years ago

The mean score of a placement exam for entrance into a math class is 80, with a standard deviation of 10. Use the empirical rul

Sedbober [7]

Answer:

47.5%

Step-by-step explanation:

5 0

3 years ago

Which of the following relations are not functions? Select all that apply

alekssr [168]

A,b,c, d that’s the answer

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3 years ago