If a recipe calls fo 2 tbsp how many tsp is that

Find the slope and y-intercept. Help a girl out I’ll give you ten points.

JulsSmile [24]

(4,4)..........................ik this is wrong

6 0

2 years ago

Read 2 more answers

Could use some help with these. They r confusing!!

Gala2k [10]

Step-by-step explanation:

The top part is a cone. It's volume is:

V = ⅓ π r² h

where r is the radius (half the diameter) and h is the height.

The bottom part is a cylinder. It's volume is:

V = π r² h

where r is the radius (half the diameter) and h is the height.

The radius of the cone is 36/2 = 18 ft, and the height is 12 ft. So the volume is:

V = ⅓ π (18 ft)² (12 ft)

V = 4,071.5 ft³

The radius of the cylinder is 36/2 = 18 ft, and the height is 39 ft. So the volume is:

V = π (18 ft)² (39 ft)

V = 39,697.2 ft³

Therefore, the total volume is:

4,071.5 ft³ + 39,697.2 ft³ ≈ 43,769 ft³

4 0

3 years ago

If anyone knows about definite integrals for calculus then please I request help! I

kicyunya [14]

Answer:

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

U-Substitution

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution.

Set u: $\displaystyle u = 4x^{-2}$
[u] Differentiate [Basic Power Rule, Derivative Properties]: $\displaystyle du = \frac{-8}{x^3} \ dx$
[Bounds] Switch: $\displaystyle \left \{ {{x = 9 ,\ u = 4(9)^{-2} = \frac{4}{81}} \atop {x = 5 ,\ u = 4(5)^{-2} = \frac{4}{25}}} \right.$

Step 3: Integrate Pt. 2

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^9_5 {\frac{-8}{x^3}e^\big{4x^{-2}}} \, dx$
[Integral] U-Substitution: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^{\frac{4}{81}}_{\frac{4}{25}} {e^\big{u}} \, du$
[Integral] Exponential Integration: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}(e^\big{u}) \bigg| \limits^{\frac{4}{81}}_{\frac{4}{25}}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8} \bigg( e^\Big{\frac{4}{81}} - e^\Big{\frac{4}{25}} \bigg)$
Simplify: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

4 0

2 years ago

A bug starts at the origin of the coordinate plane. The bug moves 1/4 units right and 1/4 units down to point A. Which graph sho

Vsevolod [243]

Answer:

<h2>The Answer would be (0.25, -0.25)</h2>

Step-by-step explanation:

Since you started at the origin of the plane, it would be obvious that your place would be 0.25 on the x-axis. The template for this would be (x,y) x- right and left. y- up and down. On the y-axis, the bug moved 0.25 DOWN to point A. That would be a negative since on the y-axis, it counts up to positives and down to negative. Similar to the x-axis, it counts right to positives, left to negatives. Hope this helped!

3 0

3 years ago

Read 2 more answers

What is the answer for this question? 6x^2 - 35x + 49 ( factorising quadratics btw)

tino4ka555 [31]

Answer:

x=7/2 x=7/3

Step-by-step explanation:

5 0

3 years ago