Answer:
no solution
Step-by-step explanation:
simplifying
6(y + -5) = 2(10 + 3y)
reorder the terms:
6(-5 + y) = 2(10 + 3y)
(-5 * 6 + y * 6) = 2(10 + 3y)
(-30 + 6y) = 2(10 + 3y)
-30 + 6y = (10 * 2 + 3y * 2)
-30 + 6y = (20 + 6y)
add '-6y' to each side of the equation.
-30 + 6y + -6y = 20 + 6y + -6y
combine like terms: 6y + -6y = 0
-30 + 0 = 20 + 6y + -6y
-30 = 20 + 6y + -6y
combine like terms: 6y + -6y = 0
-30 = 20 + 0
-30 = 20
solving for:
-30 = 20
the left and right sides are not equal, so there isn't any solution!
Answer:
D
Step-by-step explanation:
definitely
Answer:
Step-by-step explanation:
As they are similar triangles,we can write
=
⇒
=
⇒DE=15.8
Answer:
Step-by-step explanation:
we have
Substitute the value of y=27 in the equation and find the value of x
so
Answer:
ASA
ΔFGH ≅ ΔIHG ⇒ answer B
Step-by-step explanation:
* Lets revise the cases of congruence
- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and
including angle in the 2nd Δ
- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ
≅ 2 angles and the side whose joining them in the 2nd Δ
- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles
and one side in the 2ndΔ
- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse
leg of the 2nd right angle Δ
* Lets prove the two triangles FGH and IHG are congruent by on of
the cases above
∵ FG // HI and GH is transversal
∴ m∠FGH = m∠IHG ⇒ alternate angles
- In the two triangles FGH and IHG
∵ m∠FHG = m∠IGH ⇒ given
∵ m∠FGH = m∠IHG ⇒ proved
∵ GH = HG ⇒ common side
∴ ΔFGH ≅ ΔIHG ⇒ ASA
* ASA
ΔFGH ≅ ΔIHG
