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satela [25.4K]
4 years ago
14

Find the linear equation of the plane through the origin and the points (5,2,2) and (6,−1,1). equation:

Mathematics
1 answer:
Aleks [24]4 years ago
3 0
The cross of the position vectors is
.. [5, 2, 2] × [6, -1, 1] = [4, 7, -17] . . . . . the normal vector of the desired plane

Since the origin is a point in the plane, its equation can be written as
.. 4x +7y -17z = 0
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Is the long haired cat in the p generation a hybrid or pure bread explain your answer
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8 0
3 years ago
I really need help with this, please help me.
vazorg [7]

Answer:

See below.

Step-by-step explanation:

1. h

2. g

3. a

4. f

5. c

6. b

7. e

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3 0
3 years ago
What is the area of the figure?
Bad White [126]
20m ^2

Explanation:
The top part be be cut into 2 2•2 triangles. A = 4 for both of them
And the rest is a 4•4 square, so A = 16.
4 + 16 = 20

Hope this helps!
5 0
3 years ago
Solve for x. The figure is a parallelogram
Ivan

Answer:

x = 1

Step-by-step explanation:

The opposite angles in a parallelogram are congruent, then

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3 0
3 years ago
I need to know what 12 + 5 - (6×24) equals​
Morgarella [4.7K]

Answer:

-127

Step-by-step explanation:

first multiplied the ones in parentheses

12+5-144

then you add

12+5=17

17-144=-127

7 0
3 years ago
Read 2 more answers
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