1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
umka2103 [35]
3 years ago
6

Prove that the diagonals of a rectangle bisect each other. The midpoint of BD is _____

Mathematics
2 answers:
Paul [167]3 years ago
7 0

Answer:

its a,b dont pay attention to the other comments

Step-by-step explanation:

trasher [3.6K]3 years ago
6 0

Answer:

a,b

Step-by-step explanation:

in the rectangle when bisected

if mid point is taken as O

BO=OD

AO=OC

X=2a

mid point of X=2a/2=a

Y=2b

y mid point = b

You might be interested in
The measure of an angle is 31°. what is the measure of its complementary angle??​
Tanya [424]

Answer:

329 degrees

.....................

5 0
3 years ago
Read 2 more answers
Vanessa earns a base salary of $400 every week with an additional 5% commission on everything she sells. Vanessa sold $1850 wort
lys-0071 [83]

Answer:

$492.50

Step-by-step explanation:

To start off, we already know that Vanessa makes at least $400 every week. What we don't know is how much Vanessa makes from her 5% commission on what she sells.

To solve for that, we need to find what 5% of $1,850 is. This can be done by multiplying $1,850 by 5%. Remember, we need to change 5% into its decimal form (5% -> \frac{5}{100} -> 0.05).

$1,850 x 0.05 = $92.5

This means that Vanessa made $92.5 off of commissions last week. The last step is to add her base salary of $400 to her commission sales and we get our final answer.

$400 + $92.5 = $492.50

Vanessa's total pay last week was $492.50

6 0
3 years ago
The distribution of the values of a population is shown below, and a simple Random sample is drawn from the population. Based on
posledela

Answer: C

Step-by-step explanation:

Yes, because the population values appear to be normally distributed

6 0
3 years ago
I need help on this question
Helga [31]

Answer:

slope =( y2 - y1 ) ÷ (x2 - x1)

Step-by-step explanation:

p1 ( -1 , -2)

p2 (4 , 2 )

slope =

\frac{2 - ( - 2)}{4 - ( - 1)}  =  \frac{4}{5}

8 0
3 years ago
Can someone help me with this? PLs i'm so confused!
barxatty [35]
1. E. sine\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{5}{13}

2. L. cos\ A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{12}{13}

3. tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{5}{12}

4. Y. sin\ B = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{5}{13}

5. W. cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{12}{13}

6. tan\ B = \frac{b}{a} = \frac{adjacent}{opposite} = \frac{AC}{BC} = \frac{12}{5} = 2\frac{2}{5}

7. sin\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{1}{2}

8. W. cos\ A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{\sqrt{3}}{2}

9. I. tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{1}{\sqrt{3}} = \frac{1}{\sqrt{3}} * \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3}}{3}

10. sin\ B = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{1}{2}

11. E. cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{\sqrt{3}}{1} = \sqrt{3}

12. I. tan\ B = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{1}{\sqrt{3}} = \frac{1}{\sqrt{3}} * \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3}}{3}

13. U. sin\ A = \frac{a}{c} = \frac{hypotenuse}{opposite} = \frac{BC}{AB} = \frac{12}{15} = \frac{4}{5}

14. I. cos\A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{9}{15} = \frac{3}{5}

15. tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{12}{9} = \frac{4}{3} = 1\frac{1}{3}

16. R. sin\ B = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{4}{\sqrt{65}} = \frac{4}{\sqrt{65}} * \frac{\sqrt{65}}{\sqrt{65}} = \frac{4\sqrt{65}}{65}

17. M. cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{7}{4} = 1\frac{3}{4}

18. N. tan\ B = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{4}{7}

19. L. sin\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{16}{34} = \frac{8}{17}

20. H. cos\ B = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \fac{AC}{AB} = \frac{30}{34} = \frac{15}{17}

21. tan\ B = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{16}{30} = \frac{8}{15}

22. O. sin\ A = \frac{a}{c} = \frac{opposite}{hypotenuse} = \frac{BC}{AB} = \frac{1}{\sqrt{2}} = \frac{1}{\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}}{2}

23. O. cos\ A = \frac{b}{c} = \frac{adjacent}{hypotenuse} = \frac{AC}{AB} = \frac{1}{\sqrt{2}} = \frac{1}{\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}}{2}

24. N. tan\ A = \frac{a}{b} = \frac{opposite}{adjacent} = \frac{BC}{AC} = \frac{1}{1} = 1
7 0
3 years ago
Other questions:
  • 80,057.8 + 181.15 plz and after this I will be posting a whole sheet but all of it is due tomorrow so help plz
    12·1 answer
  • 3/12 irrational or rational number
    7·2 answers
  • A particular computer takes 12 minutes to download a 36​-minute TV show. How long will it take the computer to download a 2​-hou
    14·1 answer
  • Find the values of A in A=3x when x equals the given amount.<br> A=1/3 so x=<br> heeelppp
    5·1 answer
  • Plss help!!! (answer A and B individually!)
    13·1 answer
  • Find the number that makes the ratio equivalent to 1:2.<br> 8:
    10·1 answer
  • A lamp pole with a height of 10 ft casts a shadow of 3 ft. What is the height of a building that casts a shadow of 15 ft at the
    15·1 answer
  • What is the justification for each step in the solution of the equation?
    13·1 answer
  • What is the name of the polygon? please help
    8·1 answer
  • Use long division to divide. 340 ÷ 5.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!