The total length of the ribbon used is expressed as r and is a product of the number of gifts (g) and the length of ribbon tied in each gift. This relationship may be expressed by the equation,
r = (25) x (g)
I am assuming there are more than one juice box in a package so if the amount of juice boxes in each package is X and there are four packages 4X.
So 4X - 2= Answer
If we make it so that there are 6 juice boxes in each package and use the same method this is what we'll get:
24 - 2= 22
22 would be the juice boxes left over.
I hope this answers your question, if it doesn't use the same method with the number of juice boxes in a package.
Answer:
10 > v (if you don't trust me, check it yourself. Subsitute v for 10 in the first equation.
Step-by-step explanation:
1) 7 > v - 3
2) add 3 to both sides
3) so 7 plus 3 equals 10
So you basically do this
7 > v - 3 (ad 3 to both sides)
You get 10 > v (which is as simplified as possible)
Hope this helps! :)
Answer:
We know
1 jar = 500 buttons
5 people bring 330 buttons EACH
We can find/solve by...
people x buttons = total buttons
total buttons / 500 = number of jars needed
So..
5 x 330 = 1650
1650 / 500 = 3.3
Your answer:
4 jars
Explanation
It's impossible to have 3.3 jars, so you must round up.
Step-by-step explanation:
Answer:
a) 
b) 
c) term number 17 is the one that gives a value of 40
Step-by-step explanation:
a)
The sequence seems to be arithmetic, and with common difference d = 3.
Notice that when you add 3 units to the first term (-80, you get :
-8 + 3 = -5
and then -5 + 3 = -2 which is the third term.
Then, we can use the general form for the nth term of an arithmetic sequence to find its simplified form:

That in our case would give:

b)
Therefore, the term number 20 can be calculated from it:

c) in order to find which term renders 20, we use the general form we found in step a):

so term number 17 is the one that renders a value of 40