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amid [387]
3 years ago
10

Find the surface area of a rectangular prism with length 18 inches, width 6 inches, and height 4 inches.

Mathematics
1 answer:
Sever21 [200]3 years ago
4 0
If its volume (Not so sure about surface area?) than its 432 inches^3
You might be interested in
The answer choices are in the attachments
tatiyna
The first dropdown box answer is "reflection over the y axis"

See the attached image.

Note how corresponding points simply have the x coordinate negated. For example, A and M correspond
A = (2,8)
M = (-2,8)
The only difference between these two points is the x coordinate is positive for A, and negative for M

The same applies for B and N, C and O, etc etc

Whenever you negate x coordinates only, a reflection over the y axis occurs. This is the rule (x,y) ---> (-x,y)

-----------------------------------------------------------------------------------

The second dropdown box answer is the second choice

We can see this by adding 3 to the x coordinate of point M to go from -2 to 1 (-2+3 = 1). So the answer must have point V with an x coordinate of 1. The only answer choice that fits is choice 2. 


8 0
3 years ago
Lus
inessss [21]

Answer:Percent error=29%

Step-by-step explanation:

Percent error=(Estimated value-Actual value/ Actual value) × 100

Estimated value = amount of cookies Payton thought the mix could make = 36

Actual Value= Amount of cookies made= 28

Percent error= (36- 28)/ 28 x 100

=8/28 x 100

=0.2857 x 100

=28.57 rounded to 29%

6 0
3 years ago
If dave buys a sample of 70 nails and 6 are bad and 64 are good and he needs 2500 good nails how many nails should dave buy
dexar [7]

Answer:

Dave\ should\ buy\ 2735\ nails.

Step-by-step explanation:

Number\ of\ nails=70\\\\Good\ nails=64\\\\percentage\ of\ good\ nails=\frac{good\ nails}{total\ nails}\times 100\\\\percentage\ of\ good\ nails=\frac{64}{70}\times 100\\\\percentage\ of\ good\ nails=91.42857\%\\\\Let\ for\ 2500\ good\ nails\ he\ has\ to\ buy\ x\ nails\\\\91.42857\%\ of\ x=2500\\\\\frac{91.42857}{100}\times x=2500\\\\x=\frac{2500}{0.9142857}=2734.375\\\\x\approx 2735

5 0
3 years ago
What’s the range of the function on the graph?
sertanlavr [38]
D All real numbers Equal or greater that 2
6 0
3 years ago
PLEASE HELP IM BEING TIMED!!! WILL MARK BRAINLIEST FOR CORRECT ANSWER!!! 100PTS!!!
amid [387]

Answer:

B and D.

Step-by-step explanation:

We know that when we added the two functions together, we get:

h(x)=-x+9

However, when we multiplied them together, we get:

j(x)=-9x

Let's first consider what we can determine from this.

If we add them together, we get a linear equation. However, this doesn't mean that our two original functions are linear since if we have, say, -x^2 and x^2-x+9, they will cancel and form a linear equation if we add them together.

<em>However</em>, since we know that if we multiply the two functions together, we get a linear equation, this means that both our original functions must be linear.

<em>But</em>, if we multiplied two linear functions, then we should get a quadratic, since x times x will yield x².

Therefore, this means that one of our linear functions is a horizontal line with no x variable. This is the only way to have a linear equation when multiplied.

Therefore, we have determined that both of our original functions are linear functions, and one (only one of them) is a horizontal line.

Let's go through each of the answer choices.

A) Both functions must be quadratic.

This is false as we determined earlier. If this was true, then the resulting function should be a quartic and not a line. A is false.

B) Both functions must have a constant rate of change.

Remember that all linear equations have a constant rate of change.

Since we determined that both our original functions are linear equation, this means that both our functions will have a constant rate of change.

So, B is true.

C) Both functions must have a y-intercept of 0.

Remember that one of our functions is a horizontal line.

If the y-intercept was 0, then the equation of our horizontal line will be:

y=0

And we know that anything multiplied by 0 will give us 0. However, the product of our function is -9x.

So, C cannot be true.

Rather, only our linear equation (not the horizontal line) may have a y-intercept of 0.

D) The rate of change of either f(x) or g(x) must be 0.

Remember that we determined that one of our lines must a horizontal.

Remember that horizontal lines have a slope of 0. In other words, the rate of change is 0.

So, D is true.

E) The y-intercepts of f(x) and g(x) must be opposites.

Well, since B and D is are true, this must be false since we can only select two options ;D

But, we can think about this. Note that if we multiply the two functions, we have a function <em>without</em> a y-intercept.

Remember that our horizontal line is <em>not</em> 0. So, the y-intercept of the horizontal line is a number.

So, the opposite of a number is another number.

So, if we multiply two non-zero numbers, we <em>must</em> get another number.

However, from our product, j(x)=-9x, we don't have another number. The y-intercept from this is 0.

Therefore, the two y-intercepts <em>cannot</em> be opposites of each other. If it was so, then we should have a y-intercept. So, E must be false.

In fact, this means that the y-intercept of our line (not the horizontal one) <em>must </em>be 0.

So, our answers are B and D.

And we're done!

Edit: Some (minor) errors in reasoning. Sorry!

4 0
3 years ago
Read 2 more answers
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