Question

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Answer 1

$y=mx+b$
m - a slope
b - a y-intercept
$b=-\dfrac{13}{3}$
therefore  $y=mx-\dfrac{13}{3}$

Put the values of the coordinates of the point (-5; -1) to the equation

$x=-5;\ y=-1\\\\-1=m\cdot(-5)-\dfrac{13}{3}\ \ \ |\cdot3\\\\-3=-15m-13\ \ \ |+13\\\\10m=-15\ \ \ |:10\\\\m=\dfrac{-15}{10}\\\\m=-\dfrac{3}{2}$
Answer:  $y=-\dfrac{3}{2}x-\dfrac{13}{3}$