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Karo-lina-s [1.5K]
3 years ago
10

Helllpplpppppppp mehhhhh

Mathematics
1 answer:
noname [10]3 years ago
6 0
y=mx+b
m - a slope
b - a y-intercept
b=-\dfrac{13}{3}
therefore  y=mx-\dfrac{13}{3}

Put the values of the coordinates of the point (-5; -1) to the equation

x=-5;\ y=-1\\\\-1=m\cdot(-5)-\dfrac{13}{3}\ \ \ |\cdot3\\\\-3=-15m-13\ \ \ |+13\\\\10m=-15\ \ \ |:10\\\\m=\dfrac{-15}{10}\\\\m=-\dfrac{3}{2}
Answer:  y=-\dfrac{3}{2}x-\dfrac{13}{3}


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Jennifer serves the volleyball to Marsha with an upward velocity of 10.5 ft/s. The ball is 5 feet above the ground when she stri
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  0.98 seconds

Step-by-step explanation:

We assume the height of the volleyball is described by the equation for ballistic motion. We want to find the time it takes for the height to become zero.

__

<h3>motion equation</h3>

The general form of the equation of height for ballistic motion is ...

  h(t)=-16t^2+v_0t+h_0\qquad\text{$v_0$ and $h_0$ are the initial velocity and height}

The coefficient 16 in the equation is an approximation of 1/2g, where g is the acceleration due to gravity in ft/s². This means the units of time and distance are expected to be seconds and feet.

For the problem at hand, the initial velocity and height are 10.5 ft/s and 5 ft. Then the height equation is ...

  h(t) = -16t² +10.5t +5

__

<h3>reaction time</h3>

Marsha has until the ball hits the ground to react to the serve. To find out how long that is, we need to solve the height equation for t when h=0. This is most easily done using the quadratic formula with ...

  • a = -16
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  • c = 5

The solution is ...

  t=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}= \dfrac{-10.5\pm\sqrt{10.5^2-4(-16)(5)}}{2(-16)}\\\\=\dfrac{10.5\pm\sqrt{430.25}}{32}=\dfrac{21\pm\sqrt{1721}}{64}

The positive solution is ...

  t ≈ 0.976327 ≈ 0.98

Marsha has about 0.98 seconds to react before the volleyball hits the ground.

_____

<em>Additional comment</em>

After about 0.33 seconds, Marsha knows she doesn't need to react at all. The serve will not clear the net. Its maximum height is about 6' 8 5/8". A women's volleyball net is 7' 4 1/8" high. Jennifer's serve velocity must be at least 12.3 ft/s for the ball to go over the net. With that upward velocity, Marsha has about 1.06 seconds to react.

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2 years ago
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