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3 years ago

Can someone help me with this please?

Mathematics

1 answer:

Andrei [34K]3 years ago

3 0

Question 2: B

(x+4) is canceling out so it is the hole.

x+4=0 and x= -4 is the hole.

(x+1)=0 is vertical asymptote so x= -1 is vertical asypmtote.

Question 3: D

x²-5x-14 factors to (x-7) and (x+2)

(X+2 )cancel outs so it is a hole at x= -2

x-7=0 and x=7 is a vertical asymptote

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Which of the following numbers is irrational

Troyanec [42]

Answer:

Step-by-step explanation:

Irrational means cannot be put into a fraction. Or random repeating decimals is how I remember it.

√48 can be simplified to equal 4√3. √3 cannot be put into fraction form.

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2 years ago

Given f(x) = 7x – √2 and g(x) = x + √2, find (f – g)(x).

enot [183]

(f – g)(x) = 7x - √2 - (x + √2)
(f – g)(x) = 7x - √2 - x - √2
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3 years ago

I don't understand this

mars1129 [50]

The GCF is 7!!:))))))

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2 years ago

A standard deck of cards contains 52 cards. One card is selected from the deck.(a)Compute the probability of randomly selecting

Aneli [31]

a. There are four 5s that can be drawn, and $\binom43=4$ ways of drawing any three of them. There are $\binom{52}3=22,100$ ways of drawing any three cards from the deck. So the probability of drawing three 5s is

$\dfrac{\binom43}{\binom{52}3}=\dfrac4{22,100}=\dfrac1{5525}\approx0.00018$

In case you're asked about the probability of drawing a 3 or a 5 (and NOT three 5s), then there are 8 possible cards (four each of 3 and 5) that interest you, with a probability of $\frac8{52}=\frac2{13}\approx0.15$ of getting drawn.

b. Similar to the second case considered in part (a), there are now 12 cards of interest with a probability $\frac{12}{52}=\frac3{13}\approx0.23$ of being drawn.

c. There are four 6s in the deck, and thirteen diamonds, one of which is a 6. That makes 4 + 13 - 1 = 16 cards of interest (subtract 1 because the 6 of diamonds is being double counted by the 4 and 13), hence a probability of $\frac{16}{52}=\frac4{13}\approx0.31$ .

- - -

Note: $\binom nk$ is the binomial coefficient,

$\dbinom nk=\dfrac{n!}{k!(n-k)!}={}_nC_k=C(n,k)=n\text{ choose }k$

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3 years ago

The number of men in a tour group is 15 times the number of women. If there are 48 people in the group, how many are men? A. 45

ankoles [38]

A. 45 hope this is the correct answer if not, sorry!

3 0

3 years ago

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