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Alex
2 years ago
14

If Jason spend 2 2/3 hours more at the camp, he will complete 7 hours of camp counseling. How many hours has he worked as a coun

selor so far?
Mathematics
1 answer:
Levart [38]2 years ago
6 0

Answer:  so you subtract 7- 2 2/3 and you get 4 1/3 so there is your answer Jason worked 4 1/3 hours

Step-by-step explanation:

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F '(x) = sin(x) - 65<br> What is f(x)?
irakobra [83]

Hello,

f'(x) = sin(x) - 65 → f(x) = -cos(x) - 65x

6 0
1 year ago
Use the power-reducing formulas to rewrite each of the expressions in terms of the first power of the cosine. Sin^4cos^4
Katen [24]

Answer:

1/128 * (3 - 4cos2x + cos4x)

Step-by-step explanation:

See attachment for steps

6 0
2 years ago
Find the measures of the legs of isosceles triangle ABC if AB= 2x+4,BC= 3x-1,AC=x+1 and the perimeter of the triangle ABC is 34
Naddika [18.5K]
(2x+4) +(3x-1) +(x+1)=34
6x+4=34
x=5
AB=14, BC=14, AC=6
5 0
3 years ago
Read 2 more answers
Gabrielle's age is two times Mikhail's age. The sum of their ages is 81. What is Mikhail's age?
Darya [45]

Answer:

27

Step-by-step explanation:

       Let <em>g </em>be Gabrielle's age and <em>m </em>be Mikhail's age.

       We can turn the statements the problem gives us into mathematical expressions to help us solve.

       Gabrielle's age is two times Mikhail's age:

                      <em>g </em>= 2<em>m</em>

       The sum of their ages is 81:

                      <em>g </em>+ <em>m </em>= 81

       This gives us a system of equations that will allow us to solve for Gabrielle's age.

<em>g </em>+ <em>m </em>= 81

(2<em>m</em>)<em> </em>+ <em>m </em>= 81

3<em>m </em>= 81

<em>m</em> = \frac{81}{3}

<em>m </em>= 27

       If we need to solve for Gabrielle's age, we can do the following.

<em>g </em>= 2<em>m</em>

2(27)<em> </em>= <em>g</em>

54 = <em>g</em>

g = 54

Mikhail's age is 27.

Gabrielle's age is 54.

8 0
2 years ago
Read 2 more answers
How would I simplify this?<br> 8/13 ln 3 = ln h/12
Greeley [361]

Answer:

Step-by-step explanation:

I'll assume that you meant

(8/13) ln 3 = ln h/12

Applying rules of logs, we get:

(8/13) ln 3 = ln h - ln 12

                = ln h - ln 3 - ln 4         <=  because ln b*c = ln b + ln c

Then (8/13) ln 3 + ln 3 = ln h - ln 4, or

(21/13) ln 3 + ln 4 = ln h  

3^(21/13) * 4 = h                 <=  because ln b*c = ln b + ln c

8 0
2 years ago
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