Hello,
f'(x) = sin(x) - 65 → f(x) = -cos(x) - 65x
Answer:
1/128 * (3 - 4cos2x + cos4x)
Step-by-step explanation:
See attachment for steps
(2x+4) +(3x-1) +(x+1)=34
6x+4=34
x=5
AB=14, BC=14, AC=6
Answer:
27
Step-by-step explanation:
Let <em>g </em>be Gabrielle's age and <em>m </em>be Mikhail's age.
We can turn the statements the problem gives us into mathematical expressions to help us solve.
Gabrielle's age is two times Mikhail's age:
<em>g </em>= 2<em>m</em>
The sum of their ages is 81:
<em>g </em>+ <em>m </em>= 81
This gives us a system of equations that will allow us to solve for Gabrielle's age.
<em>g </em>+ <em>m </em>= 81
(2<em>m</em>)<em> </em>+ <em>m </em>= 81
3<em>m </em>= 81
<em>m</em> = 
<em>m </em>= 27
If we need to solve for Gabrielle's age, we can do the following.
<em>g </em>= 2<em>m</em>
2(27)<em> </em>= <em>g</em>
54 = <em>g</em>
g = 54
Mikhail's age is 27.
Gabrielle's age is 54.
Answer:
Step-by-step explanation:
I'll assume that you meant
(8/13) ln 3 = ln h/12
Applying rules of logs, we get:
(8/13) ln 3 = ln h - ln 12
= ln h - ln 3 - ln 4 <= because ln b*c = ln b + ln c
Then (8/13) ln 3 + ln 3 = ln h - ln 4, or
(21/13) ln 3 + ln 4 = ln h
3^(21/13) * 4 = h <= because ln b*c = ln b + ln c