Answer: 17
Steps:
1. Plug in (3) into “x” of the g(x) equation:
g(3) = (3)^2 + 4
g(3) = 9 +4
g(3) = 13
2. Plug in g(3) value into “x” of the f(x) equation:
f(g(3)) = x + 4
f(g(3)) = 13 + 4
f(g(3)) = 17
Answer:
The domain of the function (cd)(x) will be all real values of x except x = 2.
Step-by-step explanation:
The two functions are 
and d(x) = x + 3
So, (cd)(x) = 
Then, for x = 2 the function (cd)(x) will be undefined as zero in the denominator will make the function (cd)(x) undefined.
Therefore, the domain of the function (cd)(x) will be all real values of x except x = 2. (Answer)
Answer:
0.57
Step-by-step explanation:
Given that:
food = f ; c = clothes
P(f) = 0.76
P(C) = 0.49
P(fnC) = 0.28
Suppose a shopper is selected from the store at random and learn that they buy clothes. What is the probability that the shopper also buys food?
P(f Given C) = P(f | C)
P(f | c) = p(fnC) / p(C)
P(f | c) = 0.28 / 0.49
P(f | c) = 0.5714
P(f | c) = 0.57
A(3,4) B(-2.7) C(-3,2) D(3,0)
Add 1 to the 1st # of each
Add 2 to the 2nd #of each
Answer:
Ф=xπ, x={0,+∞}
Step-by-step explanation:
be 19cosФ=5cosФ+14 → 19cosФ-5cosФ-14 → 14cosФ-14=0 → cosФ=1
then, values for which cosФ=1 are Ф=0º=360º=720º........., but the values of Ф must be radians, so Ф=xπ, where x∈Z, not including the negative numbers,
x={0,1,2,3,....∞}
Note: π≅3.141592
when calculating the values, it must be done in radian mode
