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2 years ago

What is the answer for 4[8-(8)]+1

Mathematics

1 answer:

ivann1987 [24]2 years ago

7 0

Answer:1

Step-by-step explanation:

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Write each expression as an algebraic (nontrigonometric) expression in u, u > 0.

max2010maxim [7]

Answer:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

Step-by-step explanation:

We want to write the trignometric expression:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0$

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

$\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)$

Take the secant of both sides:

$\displaystyle \sec(\theta)=\frac{u}{10}$

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

$\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}$

By substitutition:

$\displaystyle= \sin(2\theta)$

Using an double-angle identity:

$=2\sin(\theta)\cos(\theta)$

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

$\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)$

Simplify. Therefore:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

4 0

2 years ago

This is very very very confusing!!!! Anyone know 8th grade stuff?

Gala2k [10]

Answer:

yes

Step-by-step explanation:

There are no repeating numbers in the domain

3 0

1 year ago

What is the amplitude, period, and phase shift of

nasty-shy [4]

Correct answer would be D. hope this helps :)

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2 years ago

?<br> 5 in<br> Q 2 in R<br> PQ =

777dan777 [17]

Answer:

What is your specific question regarding Pq?

Step-by-step explanation:

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1 year ago

1. 43 +2)what is the value of the expression

Maru [420]

Answer:

Step-by-step explanation:

This is the answer because:

1) 43 + 2 equals to 45

Hope this helps!

7 0

2 years ago