What is the magnitude of the position vector whose terminal point is (6, -4)?
1 answer:
Answer:
2√13
Step-by-step explanation:
The distance formula is useful for this. One end of the vector is (0, 0), so the measure of its length is ...
d = √((x2 -x1)² +(y2 -y1)²) = √((6 -0)² +(-4-0)²)
= √(36 +16) = √52 = √(4·13)
d = 2√13 = |(6, -4)|
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