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3 years ago

What is the magnitude of the position vector whose terminal point is (6, -4)?

Mathematics

1 answer:

Marysya12 [62]3 years ago

5 0

Answer:

2√13

Step-by-step explanation:

The distance formula is useful for this. One end of the vector is (0, 0), so the measure of its length is ...

d = √((x2 -x1)² +(y2 -y1)²) = √((6 -0)² +(-4-0)²)

= √(36 +16) = √52 = √(4·13)

d = 2√13 = |(6, -4)|

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A segment has one endpoint at the origin O and the other endpoint at A(12,36). If point B is located on OA such that OA/BA=3 the

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The distance between (8, 24) and (12, 36) is one-third of the distance between (0, 0) and (12, 36).

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We know that:

O = (0, 0)
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And point B is between these two, such that:

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Meaning, OA is 3 times BA.

Now, if we apply a factor of 1/3 to point A, we get:

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If you want to learn more about distance, you can read:

brainly.com/question/7243416

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