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3 years ago

What is the magnitude of the position vector whose terminal point is (6, -4)?

Mathematics

1 answer:

Marysya12 [62]3 years ago

5 0

Answer:

2√13

Step-by-step explanation:

The distance formula is useful for this. One end of the vector is (0, 0), so the measure of its length is ...

d = √((x2 -x1)² +(y2 -y1)²) = √((6 -0)² +(-4-0)²)

= √(36 +16) = √52 = √(4·13)

d = 2√13 = |(6, -4)|

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Nezavi [6.7K]

Answer:

$y= \frac{-1}{5} x +4$

Step-by-step explanation:

We can find the inverse function of this excercise, isolating X and then changing the variables.

$y=-5x+20\\y-20=-5x\\\frac{y-20}{-5} =x\\$

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And now we change the variables and we get the inverse function:

$y= \frac{-1}{5} x +4$

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