What is the magnitude of the position vector whose terminal point is (6, -4)?

Mathematics

1 answer:

Marysya12 [62]3 years ago

5 0

Answer:

2√13

Step-by-step explanation:

The distance formula is useful for this. One end of the vector is (0, 0), so the measure of its length is ...

d = √((x2 -x1)² +(y2 -y1)²) = √((6 -0)² +(-4-0)²)

= √(36 +16) = √52 = √(4·13)

d = 2√13 = |(6, -4)|

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Which explains how to find the quotient of the division below? Negative 3 and one-third divided by StartFraction 4 over 9 EndFra

Ulleksa [173]

Answer:

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Step-by-step explanation:

To find the quotient of the division:

$-3\dfrac13 \div \dfrac49$