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Natasha2012 [34]
3 years ago
9

(-3,1), (-17,2) find the slope of the line through each pair of points

Mathematics
1 answer:
lesantik [10]3 years ago
4 0
Slope = y2 - y1 over x2- x1
-17 - -3 over 1-2
21 over -1
So I believe it is -21
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Answers please.....​
prisoha [69]

Step-by-step explanation:

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non static

non staticnon staticnon staticnon staticnon staticnon static

4 0
3 years ago
Which of these relations on{0,1,2,3}are partial orderings? Determine the properties of a partial ordering that the others lack.
omeli [17]

Step-by-step explanation:

A = {0,1,2,3}

a): R = {(0,0),(2,2),(3,3)}

R is antisymmetric, because if the (a,b)∈R, than a=b.

R is not reflexive, because (1,1) ∉ R while 1 ∈ A.

R is transitive, because if the (a,b)∈R and (b, c) ∈ R, than a=b=c and (a,c)=(a,a)∈R.

R is not portable ordering because R is not reflexive.

b): R = {(0,0),(1,1),(2,0),(2,2),(2,3),(3,3)}

R is antisymmetric, because if the (a,b)∈R and if the (b, a) ∈ R, than a=b (since (2,0) ∈ R and (0,2) ∉ R; and (2,3) ∈ R and (3,2) ∉ R )

R is reflexive, because (a,a) ∈ R of every element a ∈ A.

R is transitive , because if the (a,b)∈R and if the ( b , c )∈R . then a = b or b = c ( since there are only two element not of the form ( a , a ) and that pair does not satisfy ( a,b ) ∈ R and ( b , a ) ∈ R ), which implies ( a , c ) = ( b , c ) ∈ R or ( a , c ) = ( a , b ) ∈ R.

R is a partial ordering, because R is reflexive, antisymmetric and transitive.

c): R =  {(0,0),(1,1),(1,2),(2,2),(3,1),(3,3)}

R is reflexive, because (a,a)∈R of every element a ∈ A.

R is antisymmetric, because if the ( a , b )∈R and if the ( b , a )∈R . then a = b ( since ( 1 , 2 )∈R and ( 2 , 1 ) ∉ R; ( 3 , 1 ) ∈ R and ( 1 , 3 ) ∉ R ).  

R is not transitive , because ( 3 , 1 ) ∈ R and ( 1 , 2 )∈R, while ( 3 , 2 ) ∈ R.

R is not a partial ordering. because R is not transitive .

d): R =  {(0,0),(1,1),(1,2),(1,3),(2,0),(2,2),(2,3), (3,0),(3,3)}

R is the reflexive, because ( a , a )∈R of every elements∈A.

R is the antisymmetric, because if the ( a , b )∈R and if the ( b , a )∈R, then a = b ( since ( 1 . 2 )∈R and ( 2 . 1 )∉R; similarly, all other elements not of the form (a,a) ).

R is not transitive, because ( 1 , 2 )∈R and ( 2 , 0 )∈R, while ( 1 . 0 )∉R.

R is not a partial ordering, because R is not transitive,

e):  R = { ( 0 , 0 ) , ( 0, 1 ) , ( 0 , 2 ) , ( 0 , 3 ) , ( 1 , 0 ) , ( 1 , 1 ) , ( 1 , 2 ) , ( 1 , 3 ) , ( 2 , 0 ) , ( 2 , 2 ) , ( 3 , 3 ) }

R is the reflexive , because ( a , a )∈R of every element a∈A .

R is not antisymmetric, because ( 1 , 0 )∈R and ( 0 , 1 )∈R while 0 is not equal to 1.

R is not transitive, because ( 2 , 0 )∈Rand ( 0 , 3 )∈R, while ( 2 , 3 )∉R .

R is not a partial ordering, because R is not the antisymmetric and not the transitive.

3 0
3 years ago
If f(x)=3x²-5x+4, then f(-2) =
igomit [66]

Answer:

Step-by-step explanation:

First let's re-write the equation:

f(x) = 3x² - 5x + 4

If f(-2). then we can re-write the equation as:

f(-2) = 3(-2)² - 5(-2) + 4

We must solve for exponent first:  (-2)² = 4

f(-2) = 3(4) - 5(-2) + 4

Then solve for multiplication:

f(-2) = 12 + 10 + 4

Finally addition:

f(-2) = 26

that means that in a function, if X = -2, then F is equal to 26

4 0
2 years ago
For what value(s) of x are the following undefined? a 5x^2+x+11/x^2−4
irga5000 [103]

Answer:

Undefined at x = 2 and x = -2

Step-by-step explanation:

(5x²+x+11)/(x²-4)

Function becomes undefined when the denominator goes to zero.

x² - 4 = 0

x = 2, -2

4 0
3 years ago
What is x?
iren2701 [21]
X = 5 - 

-7x  - 3x + 2 = -8x - 8
+ 7x                 +7x
-3x + 2 = -x - 8
+3x        +3x
2 = 2x -8
+8       +8
10 = 2x
/2      /2
x = 5
7 0
3 years ago
Read 2 more answers
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