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3 years ago

10

Which equation best represents the graph above

1 answer:

Svet_ta [14]3 years ago

7 0

Answer:

x = -1

Step-by-step explanation:

Since the line is completely vertical there is no slope.

When a line is completely vertical, the setup is x = ___ (fill in the blank with the number that the line intersects on the x axis, in this case -1.)

When a line is completely horizontal (not applicable in this problem) the setup is y = ___ (fill in the blank with the number the line intersects on the y axis.)

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PLZ HELP!!! Find the measure of BAC

marysya [2.9K]

Answer:

<BAC = 20°

Step-by-step explanation:

It is given in the question that all 9 triangle which are formed are congruent, which means that in all triangles, the angle which is formed at point A is same.

Which means 9 angles collectively can be written as 9 · <BAC

If we consider all the 9 triangles, we can see in the figure that it forms a semicircle.

A semicircle has a total sum of angles equal to 180°

So we can write that:

9 · <BAC = 180°

Simplify for <BAC

<BAC = 20°

8 0

3 years ago

WHAT IS 25/8 AS A TERMINATING DECIMAL

Mariulka [41]

25 is divided by 8
25 / 8
3.125

8 0

4 years ago

Read 2 more answers

Help me asap thanks ! :)

pychu [463]

Answer 145°

Step-by-step explanation:

( 5x+5 ) + 40° = 15x - 5

[ Reason : exterior extended angle of a triangle is always equal to the sum of two non adjacent interior angles ]

( 5x+5 ) + 40° = 15x - 5

i.e, x= 10°

put this value of x on <PGF

= 15x - 5

= 15 * 10 - 5

=145°

6 0

3 years ago

What do ( ) mean in math

White raven [17]

Answer:

Parentheses

Step-by-step explanation:

These are used to single out a part of an equation, and most times you solve the equation in these before you solve anything else.

8 0

3 years ago

Read 2 more answers

Write the standard equation of a circle having endpoints of a diameter at (-1, 6) and (9,-8).

MAXImum [283]

Answer:

$r ^{2} = (x-4)^2 + (y+1)^{2}$

Given:

endpoints at (-1, 6) and (9, -8)

Solve for:

the standard equation of a circle having endpoints of a diameter at (-1, 6) and (9,-8).

Step-by-step explanation:

$d=\sqrt{(x_{2} -x_{1})^2+(y_{2} -y_{1})^2}$

$d=\sqrt{(9-(-1))^2+(-8-6)^2}$

$d=\sqrt{10^2+-14^2}$

$d=\sqrt{100+196}$

$d=\sqrt{296}$

$d=2\sqrt{74}$

$r=\frac{d}{2}$

$r=\frac{2\sqrt{74} }{2}$

$r=\sqrt{74}$

$Center = (\frac{x_{1}+x_{2} }{2} ,\frac{y_{1}+y_{2} }{2})$

$= (\frac{-1+9}{2}, \frac{6+(-8)}{2} )$

$=(4, -1)$

$Center = (4,-1) \\and\\r = \sqrt{74}$

Equation:

$(\sqrt{74}) ^{2} = (x-4)^2 + (y+1)^{2}$

$r ^{2} = (x-4)^2 + (y+1)^{2}$

*This took forever so I hoped it helped lol*

5 0

2 years ago