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olga_2 [115]
4 years ago
10

76255 divided by 309

Mathematics
1 answer:
iris [78.8K]4 years ago
4 0
76255 divided by 309 is 246.7799353
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Please help. The survey data, and question is in the picture provided.
notka56 [123]

Answer:

\frac{83}{186}

Step-by-step explanation:

In probability, "OR" means "+" and "AND" means "*".

The total amount of people is:

32 + 54 + 78 + 112 + 96 = 372

Number of diabetic patients are 54

Number of eye patients are 112

Since we want "OR", we will add the two probabilities:

P(diabetic or eye problem) = 54/372 + 112/372 = 83/186

5 0
3 years ago
Triangle TAG is graphed as shown
solniwko [45]

Answer:

The transformation is (x,y) to (x-2,y-6)

Step-by-step explanation:

First of all, we note the coordinates of the point G

The coordinates of the point G is (2,6)

To bring this to the origin, we are looking at bringing it to the point (0,0)

To do this, we subtract 2 from the x-value and 6 from the y value

So what we have is that;

(x-2) and (y-6)

(x-2, y-6)

4 0
3 years ago
Two point charges q and 4q are at x = 0 and x = L, respectively, and free to move. A third charge isplaced so that the entire th
Ivanshal [37]

Answer:

The answers to the question are

Magnitude = 4/9·q

Sign = Opposite in sign to those of q and 4·q, that is, -ve where q and 4·q are +ve

x coordinate L/3

or +\frac{4}{9} q at x coordinate = \frac{L}{3}

Step-by-step explanation:

To solve the question, we note that

Force between charges is given by

F =k\frac{q_1q_2}{r^2}, therefore the force between the two charges q and 4q is

F = k\frac{q(4q)}{(L^2)}  = k\frac{4q^2}{L^2}

For equilibrium, the charge on the third charge p, will be opposite to those of q and 4·q and the location will be between 0 and L

Therefore the force between the p and q  placed at a distance d from q = F(pq) =  k\frac{pq}{d^2} and the force between p and 4q = F(4qp) =  k\frac{4pq}{(L-d)^2}

For equilibrium,  these two forces should be equal, therefore

k\frac{qp}{d^2}=k\frac{4pq}{(L-d)^2} which gives  \frac{qp}{d^2} = \frac{4pq}{(L-d)^2} and by cross multiplying, we have

(L-d)²× p×q = d²× 4×p×q → (L-d)² = d²× 4 = (L-d)² - d²× 4 = 0 or

L² - 2·d·L -3·d² = 0, which could be factored as

(L+d)×(L-3·d) = 0 Which gives either L = -d or L = 3·d

Since L > d as d is in between 0 and L, then the correct solution is L = 3·d

Since the system is in equilibrium then \frac{4q^2}{L^2} =  \frac{pq}{d^2} or \frac{4q^2}{(3d)^2} =  \frac{pq}{d^2}

Cancelling like terms gives \frac{4}9 q=  p

Therefore the magnitude of p = 4/9·q

The location of p is L/3 from the charge q

7 0
3 years ago
PLZ HELP I WILL MARK YOU BRAINLYEST
alexira [117]

I believe the answer is the third option.

1/2x is the slope and +3 is the Y-intercept which we already know is 3.

The graph is going up so its going to be a positive 3.

-Seth

4 0
4 years ago
Convert 35°24` dms to decimal form
jeka94
<span>35°24`  = 35 degrees plus 24/60 degrees = 35.4 degrees.

24/60 degrees is equivalent to 24 minutes.</span>
7 0
3 years ago
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