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yuradex [85]
3 years ago
15

Mr.Meyer plans to increase the width of his garden by 25%

Mathematics
1 answer:
Alenkasestr [34]3 years ago
6 0
I dont understand what you're asking me to do here...if you have anymore information, it'd be really useful!
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vesna_86 [32]
There are 4320 minutes in 3 days
5 0
2 years ago
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Taletha is preparing for an exam in Algebra II. She knows she will be expected to determine if two functions are inverses of eac
seropon [69]

Answer:

f ○ g(x) = x and g ○ f(x) = x  is the correct composition

Step-by-step explanation:

INVERSE FUNCTIONS: Two functions are said to be inverse of each other if for every y = f(x), there exists a function g(x),

such that x = f^{-1} (y) =  g(y)

Now, here if we need to show tha two functions f(x) and g(x) are inverse functions of each other , then show that for every x:

1. f  o g(x)   =   f(g(x))= x

2. g o f(x)  =  g(f(x))   = x

If any two functions satisfy these two conditions, then they are inverse of each other.

5 0
3 years ago
Evaluate:
Anni [7]

Answer:

a) = 4.5

b) = 3.3

Step-by-step explanation:

Before solving our problems given to us let us under stand the rule of cube roots

It says \sqrt[3]{x \times x \times x} = x   -----(A)

Also

\sqrt[3]{x \times x \times x \times y \times y \times y} = x \times y   ---(B)

Now let us see each part one by one

a) we have

\sqrt[3]{64} + \sqrt[3]{0.027} + \sqrt[3]{0.008}

Now 64 = 4 x 4 x 4

0.027 = 0.3 x 0.3 x 0.3

0.008 = 0.2 x 0.2 x 0.2

substituting these values

\sqrt[3]{4 \times 4 \times 4} + \sqrt[3]{0.3 \times 0.3 \times 0.3} + \sqrt[3]{0.2 \times 0.2 \times 0.2}

Applying Rule A in above

=4+0.3+0.2

=4+0.5

4.5

b) we have \sqrt[3]{0.3 \times 0.3 \times 0.3 \times 11 \times 11 \times 11}

Applying the B rule in this

=0.3 \times 11

3.3

4 0
3 years ago
A line passes through the points (-6,4) and (-2,2). Which is the equation of the line?
Art [367]
The answer is y= -1/2x + 1
3 0
3 years ago
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Una solución tiene un valor de pH=5 Cuál es la concentración molar de OH-?​
Mnenie [13.5K]

Answer:

Podemos hacer la conversión entre [\text{H}^+][H

+

]open bracket, start text, H, end text, start superscript, plus, end superscript, close bracket y \text{pH}pHstart text, p, H, end text mediante las siguientes ecuaciones:

\begin{aligned}\text{pH}&=-\log[\text{H}^+]\\ \\ [\text H^+]&=10^{-\text{pH}}\end{aligned}

pH

[H

+

]

=−log[H

+

]

=10

−pH

5 0
3 years ago
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