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Ulleksa [173]
2 years ago
12

2x+1>

- x" alt="2x + 1 \geqslant 5 - x" align="absmiddle" class="latex-formula">
5-x​
Mathematics
1 answer:
melisa1 [442]2 years ago
4 0
What are we supposed solve for? Be for specific please
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Select the appropriate linear equation for the trend line.
Maksim231197 [3]

Answer:

A y = x + 1

Step-by-step explanation:

The line starts at 1 on the y-axis so the u intercept will be 1

4 0
2 years ago
Read 2 more answers
Determine the standard form of the equation for the circle with center (h,k) = (-5 ½) and radius r =1
wariber [46]
Asuuing yo meant (h,k)=(-5,1/2)

equation is (x-h)^2+(y-k)^2=r^2
(h,k) is center and r=radious
given that (h,k)=(-5,1/2) and r=1
h=-5
k=1/2

(x-(-5))^2+(y- \frac{1}{2} )^2=1^2
(x+5)^2+(y- \frac{1}{2} )^2=1
if you wanted us to expand
x²+y^2+10x-y+25.25=1
8 0
3 years ago
WILL GIVE BRAINLST <br><br> HAVE A GOOD DAY
Sedbober [7]
1st one 17/100 2nd one 0.25


Because 0.17 would be like 17% out of 100% so the fraction simplified is 17/100

2. Since the area of a square is length×length
But according to the question we are asked to find the length and the area is given so we will have to solve this
L×L= area
L^2=0.25
Square root both sides
L=√0.25
L=0.5
Therefore the length of the square is 0.5
6 0
3 years ago
Use a net of the square pyramid, if necessary, to find the surface area of the pyramid.
katen-ka-za [31]

Answer:

128 if it wants the whole thing than 192

Step-by-step explanation:

8 0
2 years ago
Which is the equation for ---
ratelena [41]
Equation of the line: 
y=mx+b
Ordinate at the origin (where the line cut the y-axis): b=1

B=(-5,5)=(xb,yb)→xb=-5, yb=5
C=(0,1)=(xc,yc)→xc=0, yc=1
m=(yc-yb)/(xc-xb)
m=(1-5)/(0-(-5))
m=(-4)/(0+5)
m=(-4)/(5)
m=-(4/5)

y=mx+b
y=-(4/5)x+1
Multiplying the equation by 5:
5[y=-(4/5)x+1]
5y=-4x+5
Adding 4x both sides of the equation:
5y+4x=-4x+5+4x
4x+5y=5

Answer: The equation for BC is: Third option 4x+5y=5
7 0
2 years ago
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