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Tom [10]
3 years ago
7

The product of two consecutive odd integers is 1 less than four times their some. find the two integers.

Mathematics
1 answer:
nignag [31]3 years ago
7 0
2 consecutive odd integers.....x and x + 2.....the product means multiply....the sum means add.

x(x + 2) = 4(x + x + 2) - 1
x^2 + 2x = 4(2x + 2) - 1
x^2 + 2x = 8x + 8 - 1
x^2 + 2x = 8x + 7
x^2 + 2x - 8x - 7 = 0
x^2 - 6x - 7 = 0
(x - 7)(x + 1) = 0

x - 7 = 0            x + 2 = 7 + 2 = 9
x = 7
 
x + 1 = 0           x + 2 = -1 + 2 = 1
x = -1

there can be 2 answers for this....
(1) 7 and 9
(2) -1 and 1
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Answer:

26 + y

----------

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Step-by-step explanation:

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3(8-y) + (y+2) + 3y.  We must now divide this by the LCD:

3(8-y) + (y+2) + 3y

--------------------------

            9y

Next we need to perform the indicated multiplication:

24 - 3y + y + 2 + 3y

----------------------------

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and then to combine like terms:

24 + 2 - 3y + y + 3y,           26 + y

----------------------------   or    -----------

              9y                             9y

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