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Flauer [41]
3 years ago
8

Which statement is true? 7.11≤−7.1 7.11>−7.1 7.11<−7.1 7.11=−7.1

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
5 0

Answer:

7.11 > -7.1

Step-by-step explanation:

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Tan theta if sec theta= 5/2 and csc theta &lt; 0?
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Kevin gave ben $4.90 in dimes and quarters.if 10 coins were quarters how many coins were dimes which equation models this proble
Mariana [72]

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24 dimes

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4 years ago
Alex weighs 185 pounds. If he decreases his weight by 10% what would be his new weight?
PSYCHO15rus [73]

Answer:

166.5

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A statue is mounted on top of a 21 foot hill. From the base of the hill to where you are standing is 57feet and the statue subte
puteri [66]

Please find the attached diagram for a better understanding of the question.

As we can see from the diagram,

RQ = 21 feet = height of the hill

PQ = 57 feet = Distance between you and the base of the hill

SR= h=height of the statue

\angle SPR=7.1^0=Angle subtended by the statue to where you are standing.

\angle x=\angleRPQ which is unknown.

Let us begin solving now. The first step is to find the angle \angle x which can be found by using the following trigonometric ratio in \Delta PQR:

tan(x)=\frac{RQ}{PQ}=\frac{21}{57}

Which gives x to be:

x=tan^{-1} (\frac{21}{57})\approx 20.22^{0}

Now, we know that \angle x and \angle SPR will get added to give us the complete angle \angle SPQ in the right triangle \Delta PQS.

We can again use the tan trigonometric ratio in \Delta PQS to solve for the height of the statue, h.

This can be done as:

tan(\angle SPQ)=\frac{SQ}{PQ}

tan(7.1^0+20.22^0)=\frac{SR+RQ}{PQ}

tan(27.32^0)=\frac{h+21}{57}

\therefore h+21=57\times tan(27.32^0)

h\approx8.45 feet

Thus, the height of the statue is approximately, 8.45 feet.

5 0
3 years ago
Read 2 more answers
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