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frosja888 [35]
3 years ago
13

If the volume of a cube is increased by a factor of 10 (so that the new volume is 10 times the size of the original volume), by

what factor does the surface area of the cube change?
Mathematics
1 answer:
Alexeev081 [22]3 years ago
5 0

Answer:

surface area of cube 10^{\frac{2}{3} } time

Step-by-step explanation:

given data

new volume =  10 time original volume

to find out

what factor surface area change

solution

we consider here side of cube is a

and volume is V

we consider here a is 2

then volume will be v1 = a³ = 2³ = 8

and surface area = 6a²    = 6(2)² = 24    ..........1

so if volume increase 10 time

than

V = 10 × v1

a³ = 10 × 8

a³= 80

a = 2 × ∛10

and

surface area increase here

surface area = 6a²

surface area = 6( 2 × ∛10 )²

surface area = 24 × 10^{\frac{2}{3} }    ............2

so from equation 1 and 2

surface area / surface area = 24 × 10^{\frac{2}{3} }  / 24

surface area = 10^{\frac{2}{3} }

so here surface area of cube will be 10^{\frac{2}{3} } time

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