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OlgaM077 [116]
3 years ago
9

Why do perpendicular lines intersect at a right angle

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
3 0
All perpendicular lines must cross to form a right angle, meaning they intersect at a right angle.

Hope this helps!
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What is the answer of this math problem
kiruha [24]
I think it is m= 5/2 and 1/5
7 0
3 years ago
Which graph represents the solution to the given system? y=5x+4; y=5x-3
Mars2501 [29]

Hello from MrBillDoesMath!

Answer:

The lines do not intersect


Discussion:

Where do the lines intersect?

5x + 4 = 5x - 3     =>                   subtract 5x from both sides

4         =       -3      =>  NO WAY! The lines do not intersect


Thank you,

MrB

3 0
4 years ago
What is the radius of a circle with an area of 113.04 cubic inches? Use 3.14 for pi. Enter your answer in the box. in.
gizmo_the_mogwai [7]

Answer:

6 inches.  

Step-by-step explanation:

We have been given that area of a circle is 113.04 cubic inches and we are asked to find the radius of the circle.

We will use area of circle formula to find the radius of our circle.

\text{Area of circle}=\pi r^2

Upon substituting the area of given circle we will get,

113.04=\pi r^2

Substituting \pi=3.14 we will get,

113.04=3.14*r^2  

\frac{113.04}{3.14}=\frac{3.14*r^2}{3.14}  

36=r^2

Upon taking square root of both sides of our equation we will get,

r=\pm 6  

Since the radius of the circle can not be negative, therefore, the radius of circle will be 6 inches.  


4 0
3 years ago
Use the drawing tool(s) to form the correct answers on the provided graph.
lianna [129]

Answer:

  see below

Step-by-step explanation:

A graphing calculator can help you do this.

__

The function crosses the y-axis where x=0.

  g(0) = -5^0 +5 = -1 +5

  g(0) = 4

The function crosses the x-axis where g(x) = 0

  0 = -5^x +5

  5^x = 5 = 5^1

  x = 1

  g(1) = 0

The points of interest are (0, 4) and (1, 0).

7 0
3 years ago
Prove algebraically what type of function this is (even, odd, or neither).<br>f(x) = x^6 – x^4​
Savatey [412]

Let's see.

We have function f(x)=x^6-x^4. We have to determine if the function is even or odd or neither.

We can find this out in many ways but the assignment specifically asks to prove this algebraically.

Function is even if f(x)=f(-x), so, x^6-x^4=(-x)^6-(-x)^4

Which is true since negative raised to an even power is positive to that same number.

Similarly, function is odd if f(x)=-f(-x), that is,

x^6-x^4\neq-((-x)^6-(-x)^4).

So we have prooved that function f(x) is an even function not an odd function and therefore also not neither.

Hope this helps.

3 0
4 years ago
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