You do 2(5)^2 and the answer is 50
Here is a quadratic equation x^2 + 5x = 14
x^2 + 5x - 14 = 0 - Subtract 14 from both sides
(x + 7)(x - 2) = 0 - Factor
x + 7 = 0 x - 2 = 0 - Set each factor equal to 0
x = -7 x = 2 - solve each piece
If the constant is easy to find factors of then use the factoring method
If the constant is difficult and you have a graphing calculator, then graph
If no graphing calculator then use the quadratic formula
The solution to the problem is as follows:
The quotient rule is ( f'(x)g(x)-f(x)g'(x) )/ (g(x))^2 {complex written on 1 line I know}
let f(x)=9x +13 and g(x)=2x+4
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f'(x)=9 and g'(x)=2 </span>
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therefore just substitute the equations in. </span>
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y'= 6x - ((9(2x+4)-2(9x+13))/((2x+4)^2))
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The answer would be 11 because the x's 9 doesnt have to move because they're on the same point. If you take 7 away from -7 you get zero. Add 4 to that 7 and you get 11. Make sesnse?
Hope this helped!
