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Alex787 [66]
3 years ago
14

What's the completed variable table

Mathematics
1 answer:
Ksju [112]3 years ago
3 0
First one is 672 the second one is 1008 the third one is 1344 the last one is 1512
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A right rectangular prism has a volume of 470.40 cm³. The length of the solid is 6.4 cm and the width is 9.8 cm.
Bogdan [553]
V = l * w * h
470.40 = 6.4 * 9.8 * h
Multiply the length and width on the right side of the equation.

470.40 = 62.72 * h
Divide both sides by 62.72
7.5 cm = h

CHECK
V = l * w * h
V = 6.4 * 9.8 * 7.5
V = 470.4 cm^3
5 0
3 years ago
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Please help with 11c!?
Contact [7]

Answer:

"To the nearest year, it would be about 9 years"

Step-by-step explanation:

11c)

This is compound growth problem. It goes by the formula:

F=P(1+r)^t

Where

F is the future amount

P is the present (initial) amount

r is the rate of growth, in decimal

t is the time in years

Given,

P = 20,000

r = 8% = 8/100 = 0.08

F = double of initial amount = 2 * 20,000 = 40,000

We need to find t:

F=P(1+r)^t\\40,000=20,000(1+0.08)^t\\2=(1.08)^t

To solve exponentials, we can take Natural Log (Ln) of both sides:

2=(1.08)^t\\Ln(2)=Ln((1.08)^t)

Using the rule shown below we can simplify and solve:

Ln(a^b)=bLn(a)

We can write:

Ln(2)=Ln((1.08)^t)\\Ln(2)=tLn(1.08)\\t=\frac{Ln(2)}{Ln(1.08)}\\t=9.0064

To the nearest year, that would be about 9 years

5 0
3 years ago
Help pls you get 27 points
Trava [24]

Answer:

C. [-5] < [-3]   ||   D. [-4] < [-2]

Step-by-step explanation:

in A. 5 should be greater, > than -3

in B. 2 should be greater, > than -4

in C. its correct answer. true statement.

in D.  its correct answer. true statement.

5 0
2 years ago
There are 2 cats on each house roof, and there are 15 cats on the ground. The table shows how the number of cats, c, depends on
Nuetrik [128]

Answer: c = 2h + 15

Step-by-step explanation: Each house (h) adds 2 cats. We represent that with 2h. Then we add the constant 15 on the ground as +15.

4 0
3 years ago
Hi! could I have some help?​
alekssr [168]
Hey do you mind taking a better photo I’m willing to help and if you can’t message me and I’ll send you any of my socials to message me so I can help
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