Answer:
6 or 5
Step-by-step explanation:
Answer:
a) d = 36 ft. ( using Pithagoras´theorem )
b) d = 36 ft ( Using ( function sin ) trigonometry
Step-by-step explanation:
a) Using Pythagoras´Theorem:
Diagonal (d) is the hypothenuse of a right triangle of side 25 feet, and according to Pythagoras´Theorem in a right triangle.
d² = a² + b²
In this particular case a = b = 25 feet then
d² = (25)² + ( 25)²
d = √ 2 * (25)²
d = √2 * 25
d = 1,414*25
d = 35,35
d = 36 ft.
b) Using trigonometry:
We know that sin 45° = cos 45° = √2 / 2
In a right triangle
sin α = opposite side / hypothenuse (d)
sin 45° = √2 / 2 = 25/ d
√2 *d = 2* 25
d = 50/√2
d = 50 / 1,414
d = 35,36
d = 36 ft
Answer:
566 ft
Step-by-step explanation:
Given the polynomial equation
-16t² + 300t + 30 = 0
We're asked to find how high the rocket would rise in a 2 second fuse rise. This is a simple instruction that can be obtained by setting the unknown, t, in the equation to 2. Doing this, we have
-16 * 2² + 300 * 2 + 30
-16 * 4 + 600 + 30
-64 + 630 = 566 ft
Then, we can therefore conclude that the rocket will rise high up to a distance of 566 ft
Well, from 2008 to 2010 is just 2 years, so let's say the initial amount is the 19300 from 2008, how many will it be in 2010?
Answer:
A. less than three batteries were used in five hours.
