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Kay [80]
3 years ago
7

Factor the expression. d2 – 4d + 4

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
3 0
(D+2)2
Because d2 is just 2*d so it’s 2d-4d+4 subtract 2d from 4d and you get (2d+4) and you can factor out a 2 from that 2(d+2)
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If f(x)=3x+1 and g(x)=1x what is the value of (f-g)(2)
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g = 3x+1

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6 0
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-3/4(x-3)-5= 1/8 (x-1)
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I think it’s 1384939384$3
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You deposit $300 in a savings account that pays 6% interest compounded semiannually. How much will you have at the middle of the
Otrada [13]

Answer:

Please check the explanation.

Step-by-step explanation:

a)  How much will you have at the middle of the first year?

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 0.5 years

Total amount = A = ?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

substituting the values

A=300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(0.5\right)}

A=300\cdot \frac{2.06}{2}

A=\frac{618}{2}

A=309 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

Part b) How much at the end of one year?

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 1 years

Total amount = A = ?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

so substituting the values

A\:=\:300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(1\right)}

A=300\cdot \frac{2.06^2}{2^2}

A=318.27 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

7 0
3 years ago
Use the distributive property to rewrite the expression 4(3.5 + 2.3).
Fed [463]

Step-by-step explanation:

4x 3.5 + 4x 2.3

14 + 9.2

= 23.2

6 0
3 years ago
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