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ycow [4]
4 years ago
5

Your school theater just finished the opening weekend of a play, and they want to figure out how much money they made after expe

nses. Each ticket sells for $3.50, and they know that selling 200 tickets gives them a profit of $625.
Write an equation that can be used to calculate the profit (p) when they sell any given number of tickets (t)
Mathematics
1 answer:
mylen [45]4 years ago
6 0
Its how much $$ they made minus the money they spent. The difference, or sum, is their profit
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Need help. Please show work.
Alekssandra [29.7K]

Answer:

See below     PLEASE GIVE BRAINLIEST

Step-by-step explanation:

5(x -3) - x =                                        

5x - 15 -x =

5x - x - 15 =

4x - 15 =

4x = 15

x = 15 ÷ 4

x = 3.75                                     5(3.75 - 3) - x = 18.75 - 15 - 3.75 = 0

                                                 

5 0
3 years ago
5.4 is to 0.6 as 12.6 is to 1.4 true or false
puteri [66]
The answer is true.

5.4 divided by 0.6 = 9
12.6 divided by 1.4 = 9

8 0
3 years ago
G(x) = (x-5)^2 + 4 what is quadratic equation in standard form
Elena L [17]

Answer:

C is the answer

g(x)  = x² - 10 x + 29

Step-by-step explanation:

g(x) = (x -5)² + 4

       = x² - 10 x +25 +4

        = x² - 10 x + 29

∴ g(x)  = x² - 10 x + 29

3 0
3 years ago
K+5,-1 and 2k are consecutive terms of an arithmetic sequence.<br>1.find k<br>2.find the terms.​
Eddi Din [679]

Answer:

K enejwjwjenenw

Step-by-step explanation:

Serey mejw catttsn keesuyboard

8 0
3 years ago
Jodie Meeks's Free Throws During the 2015-16 NBA season, Jodie Meeks of the Detroit Pistons had a free throw shooting percentage
Damm [24]

Answer:

0.8973

Step-by-step explanation:

Relevant data provided in the question as per the question below:

Free throw shooting percentage = 0.906

Free throws = 6

At least = 5

Based on the above information, the probability is

Let us assume the X signifies the number of free throws

So,  Then X ≈ Bin (n = 6, p = 0.906)

P = (X = x) =  $\sum\limits_{x}^6 (0.906)^x (1 - 0.906)^{6-x}, x = 0,1,2,3,.., 6

Now

The Required probability = P(X ≥ 5) = P(X = 5) + P(X = 6)

=  $\sum\limits_{5}^6 (0.906)^5 (1 - 0.906)^{6-5} + $\sum\limits_{6}^6 (0.906)^6 (1 - 0.906)^{6-6}

= 0.8973

8 0
4 years ago
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