We are given with an isosceles triangle having a vertex on the curve given y =<span>27-x^2</span> .
The area of the triangle, A= xy = x (27-x^2)
A' = 27-x^2-2x^2 = 0
x = 3
Amax = 3(27-9) = 54 units2
When solving system equations, we can use substitution method or elimination. Today I'm using substitution method.
First name the 2 equations.
3x + y = 3 (1)
x + y = 2 (2)
Now pick one equation and express one algebra in forms of the other.
From (2),
x = 2 - y (3)
Now substitute (3) into (1),
3(2-y) + y = 3
6 - 3y + y = 3
6 - 2y = 3
6 - 3 = 2y
y = 1.5
Now substitute y = 1.5 into (2)
x + 1. 5 = 2
x = 2 - 1.5
x = 0.5
Therefore the answer is x = 0.5 and y = 1.5
Answer:
1) 1/10
2) 1/2
3) 1/5
Step-by-step explanation:
1)
1 favorable outcome and 10 total outcomes.

2)
5 favorable outcomes and 10 total outcomes

3)
2 favorable outcomes and 10 total outcomes

Add the exponents so 3^3 or 27
Answer:
12
Step-by-step explanation:
a=3b
b=2c
c=4d
a*c/b*d = (3(2(4d)))*(4d)/(2(4d))*d
= 96d^2/8d^2
= 12