Question

Consider the diagram below. which of the following represents the values x,y and z?

Answer 1

Answer:

$x=4\sqrt{6}\ units$

$y=4\sqrt{2}\ units$

$z=4\sqrt{3}\ units$

Step-by-step explanation:

The picture of the question in the attached figure

step 1

In the right triangle ABD

Applying the Pythagorean Theorem

$x^2=y^2+(12-4)^2$

$x^2=y^2+64$

$y^2=x^2-64$ ----> equation A

step 2

In the right triangle BDC

Applying the Pythagorean Theorem

$z^2=y^2+4^2$

$z^2=y^2+16$

$y^2=z^2-16$ ----> equation B

step 3

In the right triangle ABC

Applying the Pythagorean Theorem

$12^2=x^2+z^2$

$144=x^2+z^2$ ----> equation C

step 4

Equate equation A and equation B

$x^2-64=z^2-16$

$x^2=z^2+48$ -----> equation D

step 5

substitute equation D in equation C

$144=z^2+48+z^2$

solve for z

$2z^2=144-48$

$2z^2=96$

$z^2=48$

$z=\sqrt{48}\ units$

simplify

$z=4\sqrt{3}\ units$

Find the value of x

$x^2=z^2+48$

$x^2=48+48=96$

$x=\sqrt{96}\ units$

$x=4\sqrt{6}\ units$

Find the value of y

$y^2=z^2-16$

$y^2=48-16$

$y^2=32$

$y=\sqrt{32}\ units$

$y=4\sqrt{2}\ units$