The answer of the 6 to the power of 4 multiplied by 6 to the power of 3 over 6 to the power of 5 will be 6 to the power of 2 so option (b) will be correct.
<h3>What is multiplication?</h3>
The general mathematical operation of multiplying involves adding two or more numbers to get a new multiplied number.
Multiplication gives us a resultant number that will be very big as compared to the number which is going to be multiplied if and only if the number which is going to be multiplied is more than one.
Given,
6 to the power of 4 = 6⁴
6 to the power of 3 = 6³
6 to the power of 5 = 6⁵
So,
6 to the power of 4 multiplied by 6 to the power of 3 over 6 to the power of 5
(6⁴ × 6³)/6⁵ = 6⁷/6⁵ = 6²
Hence it will be 6 to the power two.
For more information about multiplication
brainly.com/question/14059007
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Solve: 12 - 2x = -2(y - x)
Steps:
1. Expand -2(y - x): -2y + 2x
12 - 2x = -2y + 2x
2. Then subtract 12 from both sides
12 - 12 - 2x = -2y + 2x - 12
3. Simplify,
-2x = -2y + 2x - 12
4. Then, subtract 2x from both sides
-2x - 2x = -2y + 2x - 2x - 12
5. Simplify,
-4x = -2y - 12
6. Then, divide both sides by -4
-4x/-4 = -2y/-4 - 12/-4
7. Simplify,
x = 1/2y + 3 <======= <em>Answer</em>
Hope this helped!!!!
Answer:33/9
Step-by-step explanation:
Log10(x+3)-Log10(x-3)=1
Log10((x+3)/(x-3))=1
(x+3)/(x-3)=10^1
(x+3)/(x-3)=10
Cross multiply
x+3=10(x-3)
Open brackets
x+3=10x-30
Collect like terms
10x-x=30+3
9x=33
Divide both sides by 9
9x/9=33/9
x=33/9
There are 78 cookies in box C, 26 cookies in box B and 10 cookies in box A.
let the number of cookies in first box be represented mathematically as B-16
the number of cookies in second box be represented as B
the number of cookies in third box be represented as 3B
Since there are 124 cookies we can make an equation such that it becomes
B-16 +B +3B =124
Solving for B, we have
5B -16 =124
5B =124 +16
5B =130
B=130/5
B=26
Therefore Box A contains B-16 =26-16 =10 cookies
Box C contains 3B =3 X 26=78 cookies
See similar question here: brainly.com/question/23505776
Hi there!
The question gives us the quadratic equation , and it tells us to solve it using the quadratic formula, which goes as . However, we must first find the values of a, b, and c. The official quadratic equation goes as , which matches the format of the given quadratic equation. Hence, the value of a would be 1, the value of b would be 5, and the value of c would be 3. Now, just plug it back into the quadratic equation and simplify to get the zeros of the equation.
x = \frac{-b \pm \sqrt{b^2 - 4ac} }{2a}
x = \frac{-(5) \pm \sqrt{(5)^2 - 4(1)(3)} }{2(1)}
x = \frac{-5 \pm \sqrt{25 - 12} }{2}
x = \frac{-5 \pm \sqrt{13} }{2}
x = \frac{-5 \pm 3.61 }{2}
x = \frac{-5 + 3.61 }{2}, x = \frac{-5 - 3.61 }{2}
x=-0.695 \ \textgreater \ \ \textgreater \ -0.7, x= -4.305 \ \textgreater \ \ \textgreater \ x=-4.31
Therefore, the solutions to the quadratic equation are x = -0.7 and x = -4.31. Hope this helped and have a phenomenal day!
Your answer is 4.31
