It would seem the problem requires you compute the mean, median, and standard deviation of each of the data sets. This is nicely done using the statistics functions of your graphing calculator.
Data Set A (mean, median, standard deviation) = (29.7, 29.5, √12.71)
Data Set B (mean, median, standard deviation) = (27.95, 27, √6.1475)
1. False. Data Set B is skewed to the right.
2. TRUE. 27.95 is within 3 of 29.7.
3. False. √12.71 ≠ √6.1475
4. False. The mean of Data Set A is 29.7.
5. False. Data Set A has the higher standard deviation.
6. TRUE. 29.7 is close to 29.5.
The true statements are
• the 2nd one
• the 6th one
26% × 13
26% ÷ 100 = 0.26
Then, 0.26 × 13 = 3.38
Therefore, your answer is → 3.38
Answer:
The probability of it being greater than 6 is 3/4.
Step-by-step explanation:
there are 4 outcomes, and 6 is only one of them. 3 are greater than 6, so 4 out of the 4 times the number will be greater than 6.
In y=mx +b?
If so then -3=-2(3)+b
B=3
