Answer:
Option B
Step-by-step explanation:
Again, another great question! Here we are given the following system of equations, bound by quadrant 1 -
![\begin{bmatrix}2x+7y\le \:70\\ 8x+4y\le \:136\end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D2x%2B7y%5Cle%20%5C%3A70%5C%5C%208x%2B4y%5Cle%20%5C%3A136%5Cend%7Bbmatrix%7D)
Convert this to slope - intercept form -
![\begin{bmatrix}y\le \frac{70-2x}{7}\\ y\le \:2\left(-x+17\right)\end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7Dy%5Cle%20%5Cfrac%7B70-2x%7D%7B7%7D%5C%5C%20y%5Cle%20%5C%3A2%5Cleft%28-x%2B17%5Cright%29%5Cend%7Bbmatrix%7D)
Now the graphed solution of this intersects at a shaded region with which there are 3 important point that lie on the border. They are the following -
( 0, 10 ),
( 15, 9 ),
( 17, 0 )
When these point are plugged into the main function f ( x, y ) = 2x + 6y, the point ( 15, 9 ) results in the greatest solution of 84. Thus, it is our maximum point -
<u><em>Option B</em></u>
Use the equation A=(1/2)bh
Replace b with 7
Replace h with 12
A=(1/2)(7)(12)
A=(1/2)(84)
A=42
Answer:
-1.732, 0, 2, 1.732 are all the zeros
Because this is to a power of four, I doubt you could factor it easily. Also, you can't use the rational toot theorem because the constant is 0.
Thus, just put it on a graphing calculator or graphing software like Desmos graphing calculator.
Hi!
We need to know the distance in a straight line from point N to the line LM.
There are 3 lines connecting N to LM. Two of them are diagonal and do not show the straight direct path to LM. One of them is a straight line right to LM. The length of it is 6.8.
The answer is 6.8.
Hope this helps!
-Peredhel
Answer:
8f -16f
Step-by-step explanation:
-2f(-4+8)
Distribute
-2f * -4 + -2f *8
8f -16f