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Stels [109]
3 years ago
6

You currently have 12 bottles of water on your shelf, and want to keep a minimum level of 6 bottles at all times. You average sa

les of 2 bottles per day. What is the minimum number you would order for enough bottles for 7 days
Mathematics
1 answer:
Iteru [2.4K]3 years ago
7 0

Answer:pretty sure its 20

Step-by-step explanation: so i took 7 and multiplied it by 2 because that is how much is sold every day and got 14. then added six to that and got 20. then i wrote this on my paper:

20  18  16  14  12  10  8  

S    M   T   W   T   F   S  

so by Saturday you should have 8 and that would leave you 6 on sunday after you sell 2. does that make sense?

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PLEASE HELP ASAP OF YOU DO FOD BLESS YOU BECAUSE IT WILL RAISE MY GRADE
Sati [7]

Answer:

8

Step-by-step explanation:

The basic form of the equation is y=mx+b. The b stands for the y-intercept. In this equation, 8 is b due to its position in the equation, and -8/7 is m. Since we know that 8 is b and that b is the y-intercept, we know that 8 is the y-intercept.

Hope this helps!

4 0
2 years ago
Read 2 more answers
The expected number of typographical errors on a page of a certain magazine is .2. What is the probability that an article of 10
Pavel [41]

Answer:

a) The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

Step-by-step explanation:

Given : The expected number of typographical errors on a page of a certain magazine is 0.2.

To find : What is the probability that an article of 10 pages contains

(a) 0 and (b) 2 or more typographical errors?

Solution :

Applying Poisson distribution,

N\sim Pois(0.2)

P(N=r)=\frac{e^{-np}(np)^r}{r!}

where, n is the number of words in a page

and p is the probability of every word with typographical errors.

Here, n=10 and E(N)=np=0.2

a) The probability that an article of 10 pages contains 0 typographical errors.

Substitute r=0 in formula,

P(N=0)=\frac{e^{-0.2}(0.2)^0}{0!}

P(N=0)=\frac{e^{-0.2}}{1}

P(N=0)=e^{-0.2}

P(N=0)=0.8187

The probability that an article of 10 pages contains 0 typographical errors is 0.8187.

b) The probability that an article of 10 pages contains 2 or more typographical errors.

Substitute r\geq 2 in formula,

P(N\geq 2)=1-P(N

P(N\geq 2)=1-[P(N=0)+P(N=1)]

P(N\geq 2)=1-[\frac{e^{-0.2}(0.2)^0}{0!}+\frac{e^{-0.2}(0.2)^1}{1!}]

P(N\geq 2)=1-[e^{-0.2}+e^{-0.2}(0.2)]

P(N\geq 2)=1-[0.8187+0.1637]

P(N\geq 2)=1-0.9825

P(N\geq 2)=0.0175

The probability that an article of 10 pages contains 2 or more typographical errors is 0.0175.

6 0
3 years ago
Solve this picture inserted of the problem above:) plz show how u sloved it plz and thank u:)
pantera1 [17]
200:22, 400:44, so there are 6 more marked deers left. To find them, 200/22, 9.09090909....., so 9.09090909*50 = 454.54545454 (round that and you get 455, hence the answer would be C).
7 0
4 years ago
Please help!
Dafna1 [17]

Answer:

sin A= 3/5

sin C= 4/5

cos A= 4/5

cos C= 3/5

Step-by-step explanation:

Please see the attached picture for the full solution.

6 0
3 years ago
Please help me with this question and if you don't know it, pls don't answer. thank you!
kramer

Answer:

The triangles are similar because angle N=angle E and angle F=angle H.

Angle-Angle (AA or AAA) Similarity theorem: If any two angles of a triangle are equal to any two angles of another triangle, then the two triangles are similar to each other.

Step-by-step explanation:

6 0
3 years ago
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