Someone plz help!!!!!!!

A survey organization has used the methods of our class to construct an approximate 95% confidence interval for the mean annual

lawyer [7]

Answer:

$\bar X = \frac{66000+70000}{2}= 68000$

We can estimate the margin of error with this formula:

$ME= \frac{Upper -Lower}{2}= \frac{70000-66000}{2}= 2000$

And the margin of error is given by:

$ME = z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

And we can rewrite the margin of error like this:

$ME =z_{\alpha/2}*SE$

Where $SE= \frac{\sigma}{\sqrt{n}}$

For 95% of confidence the critical value is $z_{\alpha/2}= \pm 1.96$

The Standard error would be:

$SE= \frac{ME}{z_{\alpha/2}}= \frac{2000}{1.96}= 1020.408$

For 99% of confidence the critical value is $z_{\alpha/2}= \pm 2.58$

And the new margin of error would be:

$ME = 2.58* 1020.408 = 2632.653$

And then the interval would be given by:

$Lower = 68000- 2632.653 = 65367.347$

$Upper = 68000+ 2632.653 = 70632.653$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The 95% confidence interval is given by (66000 , 70000)

We can estimate the mean with this formula:

$\bar X = \frac{66000+70000}{2}= 68000$

We can estimate the margin of error with this formula:

$ME= \frac{Upper -Lower}{2}= \frac{70000-66000}{2}= 2000$

And the margin of error is given by:

$ME = z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

And we can rewrite the margin of error like this:

$ME =z_{\alpha/2}*SE$

Where $SE= \frac{\sigma}{\sqrt{n}}$

For 95% of confidence the critical value is $z_{\alpha/2}= \pm 1.96$

The Standard error would be:

$SE= \frac{ME}{z_{\alpha/2}}= \frac{2000}{1.96}= 1020.408$

For 99% of confidence the critical value is $z_{\alpha/2}= \pm 2.58$

And the new margin of error would be:

$ME = 2.58* 1020.408 = 2632.653$

And then the interval would be given by:

$Lower = 68000- 2632.653 = 65367.347$

$Upper = 68000+ 2632.653 = 70632.653$

7 0

4 years ago

Find the value of the y-intercept of the line whose equation is 17x-12y=-36

Nastasia [14]

-12y = -17x - 36

divide through by -12:-#y = -17/-12 x + 3
slope = 17/12

5 0

3 years ago

Pedro has twice as many carrots as Martha, who has the same number of carrots as Oliver. If Pedro gives 5 carrots to Oliver, the

choli [55]

"Pedro has twice as many carrots as Martha:"
p = 2m
<span>
"If Pedro gives 5 carrots to Oliver,"
p - 5 (</span>Oliver is irrelevant.)<span>

"then Martha has 3 times as many carrots as Pedro"
</span>
m = 3(p - 5)

We know p in terms of m, so substitute it in:
m = 3(2m - 5)

Distribute the 3:
m = 6m - 15

Subtract 6m from both sides:
m-6m=-15
Combine variable terms:

-5m=-15

Divide out -5

m = -15/-5

m = 3

The answer is c) 3

3 0

3 years ago

For all real numbers a and b, if ab=0, then a=0 or b=0. True or false?

Alinara [238K]

True. For example, if 2 is a, and b was 0, then ab would automatically be 0. Both a and b can be 0 though, but at least one of them must be zero.

3 0

3 years ago

Read 2 more answers

I need help can you help me???

Gnom [1K]

Answer:

1. about 7.87 feet away

2. About 8.37 yds

Step-by-step explanation:

1. a^2+b^2=c^2

so 25+37= C^2

= 62

Square root of 62 = 7.87400787401

(About 7.87 ft away)

2. 40+30 = C^2

Square root of 70 = 8.36660026534

About 8.37

3 0

2 years ago

Read 2 more answers

Someone plz help!!!!!!!​

Someone plz help!!!!!!!