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3 years ago

6,11,16,21,....Algebraic expression______ 12th term- 30th term-

1 answer:

6 0

The pattern goes up by five. The formal for this is an=a1+(N-1)d. So the set up for the problem would be, an= 6+(12-1)5. Then do the same for the 30th term.
Hope this helps!

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Mary bowled six games this week. Her scores were 138,151,198,147,156, and 173. What was her average for those

erica [24]

The average of scores is 160.5

Step-by-step explanation:

Mean is the sum of all values divided by the number of values.

Given scores are:

138,151,198,147,156, and 173

The formula for average score is given by:

$Avg = \frac{Sum}{items}$

Putting values

$Avg = \frac{138+151+198+147+156+173}{6}\\Avg = \frac{963}{6}\\= 160.5$

The average of scores is 160.5

Keywords: Mean, Average

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3 years ago

In a standard normal distribution, what z value corresponds to 17% of the data between the mean and the z value?

hjlf

You're looking for a value $z$ such that

$\mathbb P(0$

Because the distribution is symmetric, the value of $z$ in either case will be the same.

Now, because the distribution is continuous, you have that

$0.17=\mathbb P(0$

The mean for the standard normal distribution is $0$ , and because the distribution is symmetric about its mean, it follows that $\mathbb P(Z$ .

$0.17=\mathbb P(Z$

You can consult a $z$ score table to find the corresponding score for this probability. It turns out to be $z\approx0.4399$ .

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2 years ago

I need to paint a bin rectangular bin w no top... bin length is 25mm and width of 9 mm how much paint do I need to cover bin

Nikitich [7]

Answer:

900mm of paint for all four sides

Step-by-step explanation:

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3 years ago

Question 12 (1 point)

Paraphin [41]

<h3>Answer: 5</h3>

=================================================

Explanation:

Let's consider the expression (x-y)^2. It expands out to x^2-2xy+y^2. The terms are:

x^2
-2xy
y^2

Each of those terms either has a single variable with an exponent of 2, or has the exponents add to 2. Think of 2xy as 2x^1y^1.

In short, this means that the degree of each monomial term is 2.

----------

Now consider (x-y)^3. It expands out into x^3-3x^2y+3xy^2+y^3.

We have terms that either have a single variable and the exponent is 3, or the exponents add to 3. The degree of each term is 3.

----------

This pattern continues.

In general, for (x-y)^n, where n is any positive whole number, the degree of each term in the expansion is n. If you picked any term, added the exponents, then the exponents will add to n.

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Gennadij [26K]

Answer:

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