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dybincka [34]
3 years ago
8

−8x+5−2x−4+5x− when x=2

Mathematics
2 answers:
hodyreva [135]3 years ago
3 0
<span>−8x+5−2x−4+5x
= -5x + 1
so when x = 2 then
</span>-5x + 1
= -5(2) + 1
= -9

hope it helps
Salsk061 [2.6K]3 years ago
3 0
The answer would be 
-9
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Which linear function has a y-intercept at –3?
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Answer:

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Step-by-step explanation:

Depending on the option choices and without seeing the option choices I can give you an idea of how to solve this.

Using y=mx+b we can find the y intercept by knowing that B is the value of the y Intercept

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2 years ago
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List some values of x that would make this inequality true. -2x&gt;10
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Step-by-step explanation:

4 0
3 years ago
Two different simple random samples are drawn from two different populations. The first sample consists of 30 people with 16 hav
Furkat [3]

Answer:

  • There is no significant evidence that p1 is different than p2 at 0.01 significance level.
  • 99% confidence interval for p1-p2 is  -0.171 ±0.237 that is (−0.408, 0.066)

Step-by-step explanation:

Let p1 be the proportion of the common attribute in population1

And p2 be the proportion of the same common attribute in population2

H_{0}: p1-p2=0

H_{a}: p1-p2≠0

Test statistic can be found using the equation:

z=\frac{p2-p1}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

  • p1 is the sample proportion of the common attribute in population1 (\frac{16}{30} =0.533)
  • p2 is the sample proportion of the common attribute in population2 (\frac{1337}{1900} =0.704)
  • p is the pool proportion of p1 and p2 (\frac{16+1337}{30+1900}=0.701)
  • n1 is the sample size of the people from population1 (30)
  • n2 is the sample size of the people from population2 (1900)

Then z=\frac{0.704-0.533}{\sqrt{{0.701*0.299*(\frac{1}{30} +\frac{1}{1900}) }}} ≈ 2.03

p-value of the test statistic is  0.042>0.01, therefore we fail to reject the null hypothesis. There is no significant evidence that p1 is different than p2.

99% confidence interval estimate for p1-p2 can be calculated using the equation

p1-p2±z*\sqrt{\frac{p1*(1-p1)}{n1}+\frac{p2*(1-p2)}{n2}} where

  • z is the z-statistic for the 99% confidence (2.58)

Thus 99% confidence interval is

0.533-0.704±2.58*\sqrt{\frac{0.533*0.467}{30}+\frac{0.704*0.296}{1900}} ≈ -0.171 ±0.237 that is (−0.408, 0.066)

7 0
2 years ago
21 is what percent of 40
-Dominant- [34]
To solve for this, set up a proportion.
21/40 = x/100.
Cross multiply the fraction's numerators with the denominators; 
21 x 100, 40 and x.
2100/40x.
Divide both numbers by 40 to get x.
2100/40 = 52.5
21 is 52.5% of 40.
I hope this helps!
5 0
3 years ago
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