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diamong [38]
2 years ago
12

What is -7(1+5b)+6 .......

Mathematics
1 answer:
Licemer1 [7]2 years ago
5 0
-1+5b is your answer.
You might be interested in
3( x - 2 ) + 2 (4x - 1)
Vika [28.1K]

Answer:

11x-8

Step-by-step explanation:

First distribute the 3 and 2. (Only in the parenthesis!):

3(x-2)+2(4x-1)

3x-6+8x-2

Combine like terms:

3x+8x=11x

-6-2=-8

So the answer is:

11x-8

4 0
2 years ago
Need to find volume, step by step explanation pls <br><br><br><br>​
worty [1.4K]

Given:

A figure of combination of hemisphere, cylinder and cone.

Radius of hemisphere, cylinder and cone = 6 units.

Height of cylinder = 12 units

Slant height of cone = 10 units.

To find:

The volume of the given figure.

Solution:

Volume of hemisphere is:

V_1=\dfrac{2}{3}\pi r^3

Where, r is the radius of the hemisphere.

V_1=\dfrac{2}{3}(3.14)(6)^3

V_1=\dfrac{6.28}{3}(216)

V_1=452.16

Volume of cylinder is:

V_2=\pi r^2h

Where, r is the radius of the cylinder and h is the height of the cylinder.

V_2=(3.14)(6)^2(12)

V_2=(3.14)(36)(12)

V_2=1356.48

We know that,

l^2=r^2+h^2                               [Pythagoras theorem]

Where, l is length, r is the radius and h is the height of the cone.

(10)^2=(6)^2+h^2

100-36=h^2

\sqrt{64}=h

8=h

Volume of cone is:

V_3=\dfrac{1}{3}\pi r^2h

Where, r is the radius of the cone and h is the height of the cone.

V_3=\dfrac{1}{3}(3.14)(6)^2(8)

V_3=\dfrac{25.12}{3}(36)

V_3=301.44

Now, the volume of the combined figure is:

V=V_1+V_2+V_3

V=452.16+1356.48+301.44

V=2110.08

Therefore, the volume of the given figure is 2110.08 cubic units.

7 0
2 years ago
Your bedroom ceiling is 10 feet high and is 2/3 as high as the living room ceiling.
zaharov [31]
Let me do the work right now, then I’ll let you know!!
6 0
3 years ago
Read 2 more answers
Three single-digit numbers multiply to make 504 Write the missing numbers
boyakko [2]
We will guess and check to solve this problem

504/9= 56
504/8= 63
504/7= 72
504/6= 84
.....
we can continue the pattern. However, we know that 50 is the product of 8 and 7, so we can use that number

9*8*7=504
3 0
3 years ago
I need help for this, thanks
gulaghasi [49]

(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.

---------------------------------------------------------------------------------------

(b) The following functions are positive in quadrant III:

tangent, cotangent

The following functions are negative in quadrant III

cosine, sine, secant, cosecant

A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.

5 0
3 years ago
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