Answer:
11x-8
Step-by-step explanation:
First distribute the 3 and 2. (Only in the parenthesis!):
3(x-2)+2(4x-1)
3x-6+8x-2
Combine like terms:
3x+8x=11x
-6-2=-8
So the answer is:
11x-8
Given:
A figure of combination of hemisphere, cylinder and cone.
Radius of hemisphere, cylinder and cone = 6 units.
Height of cylinder = 12 units
Slant height of cone = 10 units.
To find:
The volume of the given figure.
Solution:
Volume of hemisphere is:

Where, r is the radius of the hemisphere.



Volume of cylinder is:

Where, r is the radius of the cylinder and h is the height of the cylinder.



We know that,
[Pythagoras theorem]
Where, l is length, r is the radius and h is the height of the cone.

Volume of cone is:

Where, r is the radius of the cone and h is the height of the cone.



Now, the volume of the combined figure is:



Therefore, the volume of the given figure is 2110.08 cubic units.
Let me do the work right now, then I’ll let you know!!
We will guess and check to solve this problem
504/9= 56
504/8= 63
504/7= 72
504/6= 84
.....
we can continue the pattern. However, we know that 50 is the product of 8 and 7, so we can use that number
9*8*7=504
(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
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(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.