Answer:
none of the above
Step-by-step explanation:
A <em>Hamilton path</em> is one that visits each node exactly once. In a graph with 6 nodes, the path length must be exactly 6.
Only one answer choice is of length 6: ADEFBC. However, it includes travel from F to B, which path does not exist in the graph shown. Hence the only viable choice is not an answer.
_____
Some possibilities include ...
DECBAF
DABCEF
The answer is the second option y= -2x + 11
8x9=72 ft squared
4x3=12 ft squared
72+12=84 ft squared
Answer:
a) 32
b) 67.613
Step-by-step explanation:
<em><u> In Game 3, Emerson struck out 42 times in 140 times at-bat.</u></em>
<em><u>Part A</u></em>
<em><u>Drag numbers to complete the proportion to represent the percent of strikeouts per at-bats.</u></em>
<em><u>Numbers may be used once or not at all.</u></em>
<em><u /></em>
<em><u>Part B</u></em>
<em><u>What percentage of times at bat did Emerson actually hit the ball?</u></em>
Part A
Total number of strikeouts= 30+40+42= 112
Total number of at bats = 90+120+140= 350
strikeouts : times
112: 350
p:100
Using cross product rule
p/100= 112/350
p * 350= 112*100
or p= 11200/350= 32
It means that there were 32 strikeouts if 100 times were bat at hits.
Part B:
Total number of strikeouts= 30+40+42= 112
Total number of at bats = 90+120+140= 350
But we need the percentage of times at bat hit
Therefore
Hits= times - strikeouts= 350-112= 238
Percentage = 238/352*100= 67.613
Check
The above answers are correct because
100-32 = 68
68 ≅ 67.613
Answer:
Option D) 64
Step-by-step explanation:
see the attached figure with letters to better understand the problem
<em>In the right triangle BCD find BC</em>
Applying the Pythagoras Theorem

<em>In the right triangle ABC</em>

substitute the values
-------> equation A
<em>In the right triangle BDC</em>

substitute the values
-------> equation B
equate equation A and equation B
