All categories

3 years ago

What is the lateral area of the rectangular prism? Assume the prism is resting on its base.

2 answers:

7 0

<span>A rectangular prism has four lateral surfaces. If the sides of the base are L and W, two of the lateral surfaces are rectangles of side L and H, and the other two are rectangles of sides W and H. Then, the lateral area is the sum of the areas of the four lateral rectangles: 2 * L * H + 2 * W * H= 10 * 4 = 2 * 10 * 4 + 2 * 5 * 4 = 2*40 + 2 * 20 = 80 + 40 = 120.</span>

aleksklad [387]3 years ago

3 0

Answer:180

Step-by-step explanation: the correct answer is 120 but on k12 it is 180. Just took the test

You might be interested in

If (x) = x/2 -3 and g(x) = 3 x 2 + x - 6 , find (f+g) (x)

olchik [2.2K]

I believe it’s -12x but I may be wrong I hope this helped!

6 0

3 years ago

Read 2 more answers

How can I solve this equation X-5=0.1(x+5)

Artist 52 [7]

Answer:

X=6.1

Step-by-step explanation:

x-5=0.1(x+5)

x-5=0.1x+0.5 (distribute 0.1)

x=0.1x+0.5+5 (add 5 to each side)

x-0.1x=5.5 (subtract 0.1x from each side)

0.9x=5.5 (combine like terms)

x=5.5/0.9 (divide by 0.9 on both sides)

x=6.1 (simplify)

5 0

3 years ago

Read 2 more answers

Hurry please!!Gregory collected two random samples of 100 Woman regarding woman's color bag

nikitadnepr [17]

More women prefer black bags than red or blue bags. ( i hoped this help, i took this test or had a similar question and that is what i put)

6 0

2 years ago

Marvin lives in Stormwind City and works as an engineer in the city of Ironforge. In the morning, he has 333 transportation opti

sukhopar [10]

The event "Atleast once" is the complement of event "None".

So, the probability that Marvin teleports atleast once per day will the compliment of probability that he does not teleports during the day. Therefore, first we need to find the probability that Marvin does not teleports during the day.

At Morning, the probability that Marvin does not teleport = 2/3

Likewise, the probability tha Marvin does not teleport during evening is also 2/3.

Since the two events are independent i.e. his choice during morning is not affecting his choice during the evening, the probability that he does not teleports during the day will be the product of both individual probabilities.

So, the probability that Marvin does not teleport during the day = $\frac{2}{3}*\frac{2}{3}=\frac{4}{9}$

Probability that Marvin teleports atleast once during the day = 1 - Probability that Marvin does not teleport during the day.

Probability that Marvin teleports atleast once during the day = $1-\frac{4}{9}=\frac{5}{9}$

5 0

3 years ago

I don't know how to do this. I forget plz help

Leno4ka [110]

Ok so
0.5%=0.005
0.005x=8
x=8/0.005
x=1600
8 is 0.5% of 1600
Hope this helps
If u still don't understand plz message me
If u understand plz brainlest me
If you continue with the same formula with a different problem then you will get it correct
Thank you!

3 0

3 years ago

Read 2 more answers