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Marizza181 [45]
4 years ago
7

Hi! I was wondering if you could help with this question please :)​

Mathematics
1 answer:
Makovka662 [10]4 years ago
7 0

Answer:

R=\frac{QJ}{I^2t}

Step-by-step explanation:

So we have the equation:

Q=\frac{I^2Rt}{J}

And we want to solve for R.

First, let's multiply both sides by J to remove the fraction on the right. So:

(J)Q=(J)\frac{I^2Rt}{J}

Simplify the right:

JQ=I^2Rt

We can rewrite our equation as:

JQ=R(I^2t)

So, to isolate the R variable, divide both sides by I²t:

\frac{JQ}{I^2t}=\frac{R(I^2t)}{I^2t}

The right side cancels, so:

R=\frac{QJ}{I^2t}

And we are done!

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If x = 45, y = 63, and the measure of AC = 4 units, what is the difference in length between segments AB and AD? Round your answ
kondaur [170]

Answer:

1.17

Step-by-step explanation:

(MUCH BETTER!)

From the definition of the sin of an angle, you know:

sin(45°) = AC/AB = 4/AB   ⇒   AB = 4/sin(45°) ≈ 5.6569

sin(63°) = AC/AD = 4/AD   ⇒   AD = 4/sin(63°) ≈ 4.4893

Then the difference AB-AD is:

AB -AD = 5.6569 -4.4893 = 1.1676

AB -AD ≈ 1.17 units

Sorry this took me so long to answer!

8 0
3 years ago
If a farmer can trade four chickens for a pig, three pigs for two sheep, and five sheep for two cows, what is the minimum number
Deffense [45]

Answer:

The minimum of cows he needs are: 2

Step-by-step explanation:

There's a relation between each animal:

5 chickens equals 1 pig

3 pigs equals 2 sheep

5 sheep equals 2 cows

You can understand it as the following three abstractions:

5c = 1p              (1)

3p = 2s             (2)

5s = 2o             (3)

Where:

c is for chickens

p is for pigs

s is for sheep

o is for cows

So now you have three equations with 4 variables. The next step is to obtain an equation that relates directly the variable c (chickens) with the variable o (cows). In order to do that from the equation 2 we obtain s in terms of p, as follow:

3p =2s\\s=\frac{3p}{2} \\

Then we replace s in the equation 3 and we obtain v in terms of p:

5(\frac{3p}{2} )=2v\\\\2v=\frac{15}{2} p\\\\

v=\frac{15}{2*2} p \\\\v=\frac{15}{4} p

Now we replace v in the equation 1:

4c = \frac{4}{15} v

c=\frac{1}{15} v                    (4)

The equation 4 means that  1 chicken equals the fifteenth part of a cow. For this case the farmer needs 20 chikens, so we multiply per 20 each part of the equation 4:

20c = 20 * \frac{1}{15} v\\ \\\ 20c = \frac{20}{15}v = \frac{4}{3}v \\\\20c = 1.3333v

As it is impossible to have 1.3333 cows, the answer  is 2 cows approximately.

3 0
3 years ago
Read 2 more answers
Using π = 3.14, what is the circumference of a circle with a radius of 18 units? Round your answer to the nearest hundredth.
sasho [114]

Circumference - 2 x PI x radius

Circumference - 2 x 3.14 x 18 = 113.04 units

3 0
3 years ago
the area of a square is A = s^2, where s is the length of one side of the square. what is the side length s for each square ? th
vlada-n [284]

Answer:

18

Step-by-step explanation:

324 = s^2 -->

sqrt324 = s -->

sqrt(2^2 * 9^2) = s -->

2*9 = s -->

18 = s

5 0
3 years ago
There are 438 students at a middle school. If 38% of the students participate in after school sports what would the number of st
umka21 [38]

Answer:166

Step-by-step explanation:438x.38=166

438 being the total amount of students

.38 being the 38% involved (moved percentage two to the left to make it a decimal)

6 0
3 years ago
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