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Misha Larkins [42]
3 years ago
7

The graph of a sinusoidal function has a minimum point at (0,3)(0,3) and then intersects its midline at (5π,5)

Mathematics
1 answer:
bekas [8.4K]3 years ago
8 0

Answer: F(x) = 2*sin(x/10  +(3/2)*pi) + 5

Step-by-step explanation:

The information that we have is that:

We have a minimum at (0, 3)

the midline is at (5*pi, 5)

This is a sinusoidal function, so we can write one generic one as:

F(x) = A*sin(c*x + p) + B.

where A and B are constants, c is the frequency and p is a phase

First, the minimum of the sine function is when sin(x) = -1, and this happens at (3/2)*pi

We know that this minimum is at x = 0.

sin(c*0 + p) = -1

Then p = 3/2*pi.

So our function is:

F(x) = A*sin(c*x  +(3/2)*pi) + B.

Now, we know that F(0) = 3, so:

3 = A*sin(c*0 +(3/2)*pi) + B = -A + B.

now we can use the other hint, the midpoint of the sine function is when sin(x) = 0, and this happens at x = 0 and x = pi, particularlly as we here have a phase of 3/2*pi, we should find x = 2*pi.

then:

c*5*pi + (3/2)*pi = 2*pi

c*5 + 3/2 = 2

c*5 = 2 - 3/2 = 1/2

C = 1/2*5 = 1/10

So our function is

F(x) = A*sin(x/10  +(3/2)*pi) + B

and we know that when x = 5*pi, F(5*pi) = 5, so:

5 = F(x) = A*sin(5*pi/10  +(3/2)*pi) + B

5 = B

and we aready knew that:

- A + B = 3

-A + 5 = 3

A = 5 - 3 = 2

So our equation is:

F(x) = 2*sin(x/10  +(3/2)*pi) + 5

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Simplify, 99/121 whats the GCF?
Nadya [2.5K]

To find the GCF:

-- List the factors of the first number.
-- List the factors of the second number.
-- Make a short list of the factors that show up for BOTH numbers.
-- Find the biggest number on the short list.

Factors of the first number (99):  <u>1</u>, 3, 9, <u>11</u>, 33, 99 .

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Answer:

The cost of renting the car for 20 days is $481

Step-by-step explanation:

The table of values can be formed as follows;

Day,   Cost

1,         $44

2,        $67

3,        $90

4,        $113

7,        $182

10,      $251

From the given values and the scatter plot, there is a straight line relationship between the cost and the number of days of rental of a car.

The line of best fit is therefore a straight line and from the constant increase in cost ($23) for each extra day of rental, it is possible to find the slope, m, of the data as follows;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

(x₁, y,) and (x₂, y₂) can be taken as (1, $44) and (3, $90) respectively to give;

Slope, \, m =\dfrac{90-44}{3-1} = \dfrac{46}{2} = 23 \ as \ stated \ above

The equation in slope and intercept form is therefore, y  - 44 = 23×(x - 1), which gives;

y - 44 = 23·x - 23

y = 23·x - 23 + 44 = 23·x + 21

The cost of renting the car for 20 days is then;

10×23 + 21 = $481

The cost of renting the car for 20 days = $481.

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