All categories

2 years ago

If y=14 when x=8, Find y when x=12

Mathematics

2 answers:

Maksim231197 [3]2 years ago

8 0

Y would be 21

X/2 = 4
Y/2 = 7

X x 3 = 12
Y x 3 = 7x3 = 21

Good luck!

PilotLPTM [1.2K]2 years ago

5 0

y=18 when x=12 if y=14 when x=8.

You might be interested in

5x6 = (_X 6) + (2x_)

kati45 [8]

Answer:

Step-by-step explanation:

6 0

2 years ago

Select the correct answer.

gizmo_the_mogwai [7]

Answer:

Factors are (x-1), (x+1), and (x+2).

Step-by-step explanation:

$g(x)=x^{3}+2x^{2} -x-2\\g(x)=(x - 1) (x + 1) (x + 2)$

7 0

2 years ago

What is an equation of the line that passes through the point (-2 1) and is parallel to the line whose equation is 4x-2y=8 ?

monitta

4x-2y=8 ==> y=2x-4 (to better show you what I mean)

2 lines are parallel if they have the same slope (m the coefficient of x).

So y=mx + b // y =2x-4 means m=2 & y=mx + b, becomes y=2x + b.
Moreover they are telling us that this function passes by (-2,1), where -2 represents x & 1, represents y. To calculate b , replace x & y by their values:
y=2x+b ==> 1 = 2(- 2) + b==> 1 = -4 + b ==> b= 5. Finally the equation is
y=-2x+5

4 0

3 years ago

If a scale drawing has a scale of 1 centimetre to 4 meters which measurements are correct

andrew-mc [135]

Answer: Statements 2 and 3

Step-by-step explanation:

On a drawing scale;

1cm - 4m

4CM - 16M (MULTIPLYING BY 4)

6cm - 24m (multiplying by 6)

7cm - 28m (multiplying by 7)

8cm - 32m (multiplying by 8)

9CM - 36M (MULTIPLYING BY 9)

3 0

3 years ago

NEED ASAP plz. I will also mark brainiest! Don't just take points, I will report you.

PilotLPTM [1.2K]

Part A:

You may choose the two lines connecting the origin and points A and B, and choose the portion of the space between them.

The line between the origin and A is

$y = 3x$

We want everything below this line (line included), so the first inequality is

$y \leq 3x$

The line between the origin and B is

$y = \dfrac{1}{3}x$

We want everything above this line (line included), so the second inequality is

$y \geq \dfrac{1}{3}x$

Create a system with these two inequalities and you'll have an area including only points A and B

Part B:

To verify the solutions, we can plug the coordinates of A and B in this system and check that we get something true: the coordinates of point A are (1,3), while the coordinates of point B are (3,1). The system becomes:

$A:\begin{cases}3 \leq 3\cdot 1\\3 \geq \frac{1}{3}\cdot 1\end{cases},\quad B:\begin{cases}1 \leq 3\cdot 3\\1 \geq \frac{1}{3}\cdot 3\end{cases}$

Which means

$A:\begin{cases}3 \leq 3\\3 \geq \frac{1}{3}\end{cases},\quad B:\begin{cases}1 \leq 9\\1 \geq 1\end{cases}$

And these are all true. So, the system is satisfied, which means that the points belong to the shaded area.

Part C

If you draw the line, you'll see that the only points that lay below the line are B and C. In fact, if we plug the coordinates we have

$B:\ 1$

And this are both true. You can check the coordinates of all other points, and see that they won't satisfy the inequality y<3x-6

3 0

2 years ago