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Rama09 [41]
3 years ago
11

Find the missing side. Round your answer to the nearest hundredth. х 28° 42 in in

Mathematics
1 answer:
sleet_krkn [62]3 years ago
6 0

Answer:

The length of the missing side x = 47.57 in    

Step-by-step explanation:

Given

Ф = 28°

The length of the side adjacent to the angle Ф is = 42 in

To determine

The hypotenuse x = ?

Using the trigonometric ratio

cos Ф = adjacent / hypotenuse

substitute adjacent = 42 in, hypotenuse = x and Ф = 28°

cos 28° = 42 / x

x = 42 / cos 28°

x = 47.57 in      

Therefore, the length of the missing side x = 47.57 in    

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Jane randomly opens a 24 page magazine. find the probability that she would open it up to a page that is a prime number.How many
prohojiy [21]
The probability that Jane opens a prime page in a 24-page magazine is 0.375. There are 9 prime numbers between 1-24 and they are: 2,3,5,7,11,13,17,19, and 23. To calculate, Probability = Events/Number of Outcomes which is 9/24 = 0.375. Hope this helps.
7 0
3 years ago
Read 2 more answers
Please help this is so confusing u can have 25 points if u help me
Elina [12.6K]

Step-by-step explanation:

Share 20pounds in the ratio 2:3

Total ratio=2+3=5

2/5×20=8

20-8=12

Sharing 20pounds in that ratio gives 8pounds:12pounds

Share 15cm in the ratio 1:3

Total ratio=1+4=4

¼×15=3.75

15-3.75=11.25

Sharing 15cm in that ratio gives 3.75:11.25

7 0
2 years ago
Two competitive neighbours build rectangular pools that cover the same area but are different shapes. Pool A has a width of (x +
GenaCL600 [577]

<u>Answer: </u>

a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

b) Area of pool A is equal to area of pool B equal to 24.44 meters.

<u> Solution: </u>

Let’s first calculate area of pool A .

Given that width of the pool A = (x+3)  

Length of the pool A is 3 meter longer than its width.

So length of pool A = (x+3) + 3 =(x + 6)

Area of rectangle = length x width

So area of pool A =(x+6) (x+3)        ------(1)

Let’s calculate area of pool B

Given that length of pool B is double of width of pool A.

So length of pool B = 2(x+3) =(2x + 6) m

Width of pool B is 4 meter shorter than its length,

So width of pool B = (2x +6 ) – 4 = 2x + 2

Area of rectangle = length x width

So area of pool B =(2x+6)(2x+2)        ------(2)

Since area of pool A is equal to area of pool B, so from equation (1) and (2)

(x+6) (x+3) =(2x+6) (2x+2)    

On solving above equation for x    

(x+6) (x+3) =2(x+3) (2x+2)  

x+6 = 4x + 4    

x-4x = 4 – 6

x = \frac{2}{3}

Dimension of pool A

Length = x+6 = (\frac{2}{3}) +6 = 6.667m

Width = x +3 = (\frac{2}{3}) +3 = 3.667m

Dimension of pool B

Length = 2x +6 = 2(\frac{2}{3}) + 6 = \frac{22}{3} = 7.333m

Width = 2x + 2 = 2(\frac{2}{3}) + 2 = \frac{10}{3} = 3.333m

Verifying the area:

Area of pool A = (\frac{20}{3}) x (\frac{11}{3}) = \frac{220}{9} = 24.44 meter

Area of pool B = (\frac{22}{3}) x (\frac{10}{3}) = \frac{220}{9} = 24.44 meter

Summarizing the results:

(a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

(b)Area of pool A is equal to Area of pool B equal to 24.44 meters.

5 0
3 years ago
1. Yvonne closes her eyes and picks a candy from the bag, hoping for a blueberry. What are the chances she will pick a blueberry
elixir [45]

how many candy in the bag

5 0
3 years ago
Write an equivalent expression for 4(3a+7)+3 (2a+5) if a=5, is the the solution to both expressions the same
Levart [38]
<span>Alternative</span>
4(3*5+7)+3(2*5+5)=
4(22)+3(15)=
(4*22)+(3*15)=
88+45=133

4 0
2 years ago
Read 2 more answers
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